Problem 16
<h3>Answer: i</h3>
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Work Shown:
The exponent 41 divided by 4 leads to
41/4 = 10 remainder 1
The "remainder 1" means that
i^(41) = i^1 = i
The reason why I divided by 4 is because the pattern shown below
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
repeats itself over and over. So this is a block of four items repeated forever.
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Problem 18
<h3>Answer: 1</h3>
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Work Shown:
Divide 3136 over 4 to get
3136/4 = 784 remainder 0
Therefore,
i^3136 = i^0 = 1
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Problem 20
<h3>Answer: i</h3>
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Work Shown:
Combine i^6*i^7 into i^13. We add the exponents here
Now divide by 4 to find the remainder
13/4 = 3 remainder 1
So, i^13 = i^1 = i
Answer:
W = 21.44*10⁶J
Step-by-step explanation:
Given
y = x² (0 < x < 4)
γ = 10000 N/m³
W = ?
If we apply
y = 4² = 16 = h
y = x² ⇒ x = √y
then
V = π*(√y)²*dy = π*y*dy
W = (γ*V) *(16-y) = γ*π*y*dy*(16-y)
⇒ W = γ*π*∫y*(16-y)dy = γ*π*(8y²-(y³/3))
finally we obtain (0 < y < 16)
W = γ*π*(8y²-(y³/3)) = 10000*π*(8*16²-(16³/3)) = 21.44*10⁶J
Answer:
x = 5, -1
Step-by-step explanation:
0 = 3x^2 - 12x - 15 or
3x^2 - 12x - 15 = 0
By solving for x, use the Quadratic Formula.
… x = 5 and/or -1
Answer:
C. 11.4
Step-by-step explanation:
I already answered this…
