Which set of ordered pairs represents y as a function of x?

In Hamilton County, Ohio the mean number of days needed to sell a home is days (Cincinnati Multiple Listing Service, April, 2012

Diano4ka-milaya [45]

Answer:

$t=\frac{80-86}{\frac{20}{\sqrt{40}}}=-1.8974$

$p_v =2*P(t_{39}$

If we compare the p value with a significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, so there is not enough evidence to conclude that the mean for the data is significantly different from 86 days.

Step-by-step explanation:

Assuming the following problem: "In Hamilton County, Ohio the mean number of days needed to sell a home is 86 days (Cincinnati Multiple Listing Service, April, 2012). Data for the sale 40 of homes in a nearby county showed a sample mean of 80 days with a sample standard deviation of 20 days. Conduct a hypotheses test to determine whether the mean number of days until a home is sold is different than the Hamilton county mean of 86 days in the nearby county. "

1) Data given and notation

$\bar X=80$ represent the sample mean

$s=20$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =86$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is different from 86, the system of hypothesis would be:

Null hypothesis: $\mu = 86$

Alternative hypothesis: $\mu \neq 86$

We don't know the population deviation, so for this case we can use the t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{80-86}{\frac{20}{\sqrt{40}}}=-1.8974$

4) Calculate the P-value

First we need to find the degrees of freedom given by:

$df=n-1=40-1=39$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{39}$

In Excel we can use the following formula to find the p value "=2*T.DIST(-1.8974,39,TRUE)"

5) Conclusion

If we compare the p value with a significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, so there is not enough evidence to conclude that the mean for the data is significantly different from 86 days.

7 0

3 years ago

Please help with geometry

Citrus2011 [14]

The answer is B.

172.0 in.²

5 0

2 years ago

The isotope cobalt-60 has a nuclear mass of 59.933820 u

Lesechka [4]

Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.

The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:

27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u

The actual mass of the nucleus of 60-Co is 59.933820 u.

Mass defect: 60.497220 u - 59.933820 u = 0.563400 u

The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2

(0.563400 u)*(931.5 MeV/u) = 524.807 MeV

3 0

3 years ago

What is the equation of the line that passes through the point (5, 4) and has a slope of 6/5

Sati [7]

Answer:

y=6/5x-2

Step-by-step explanation:

y=mx+C

Y=6/5X+C

4=6+c

c=-2

y=6/5x-2

5 0

3 years ago

1. Simplify the following expressions. Part A: 2x3y3 4y²

Vladimir79 [104]

Answer:

204xy^(3)

Step-by-step explanation:

4 0

3 years ago

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