<h3>
Answer: 2</h3>
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Explanation:
The function f(x) = -4x+1 is the same as y = -4x+1 where y = f(x)
Compare this to y = mx+b and we see the slope here is m = -4
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Now let's find the slope of g(x)
use the slope formula with any two rows you want. I'll pick on the last two rows.
m = (y2-y1)/(x2-x1)
m = (21-9)/(3-1)
m = 12/2
m = 6 is the slope of g(x)
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From here, we add the two slope values
(slope of f)+(slope of g) = -4+6 = 2
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
3.2128 is a rational number
Answer:
t =17 years
Step-by-step explanation:
The formula for interest
A = P(1+ r/n)^ nt
where a is the amount in the account , p is the principal, r is the rate, n is the number of times compounded per year and t is the time in years
Substituting in what we know
690 = 460 ( 1+ .024/365)^ 365t
690/460 = ( 1+ .024/365)^ 365t
1.5 = ( 1+ .024/365)^ 365t
Taking the log of each side
log(1.5) = 365t log( 1+ .024/365))
Dividing each side by( 1+ .024/365)
log(1.5)/ log( 1+ .024/365) = 365t
divide each side by 365
1/365 log(1.5)/ log( 1+ .024/365) =t
t =16.8949
To the nearest year
t =17
