Consider ∆JWZ and ∆JKZ
WZ~KJ (given)
<u>/</u><u> </u><u>WZJ</u>~<u>/</u><u> </u>KJZ (given)
JZ~JZ (common)
Therefore,
∆JWZ~∆JKZ by SAS congruence rule.
JW~ZK by CPCT.
3x-10y=-25
4x+40y=20
12x-40y=-100
12x+120y=60
-160y=40
y=1/4
x=5/2
Answer:
14.3%
Step-by-step explanation:
6400-5600=800
800/6400×100=14.3
Nobody never knows the future holds itself.