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allochka39001 [22]

2 years ago

10

Find the equation (in terms of x ) of the line through the points (-3,4) and (1,-8)

2 answers:

sweet [91]2 years ago

8 0

Answer:

y = -3x - 5

Step-by-step explanation:

-3, 4 and 1, -8

1 - -3 = 4

-8 - 4 = -12

$\frac{-12}{4}$ = $\frac{-3}{1}$ = -3

gradient/slope = -3

now substituting in the point -3, 4 to find the y intercept:

4= -3 x -3 + c

4 = 9 + c

-5 = c

y intercept = -5

equation is y = -3x - 5

OLEGan [10]2 years ago

7 0

Answer:

A(-3,4) B(1,-8)

y-y1/x-x1 =y2-y1/x2-x1

y-4/x--3 = -8-4/1--3

y-4/x+3 = -12/1+3

y-4/x+3 =-12/4

y-4/x+3 = -3

y-4 = -3(x+3)

y-4=-3x-9

y+3x +9-4=

y+3x+5=0

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Tyler selects one card from the three(4,5, and a King), and rolls a number cube. What is the probability that she selects the 5,

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Step-by-step explanation:

given that Tyler selects one card from the three(4,5, and a King), and rolls a number cube.

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2 years ago

Find the value of k so that the graph of 13y + kx = 4 and the line containing the points (5, -8) and (2, 4) are parallel.

guajiro [1.7K]

the graph of 13y + kx = 4 and the line containing the points (5, -8) and (2, 4) are parallel.

We find the slope of parallel line using two given points

(5, -8) and (2, 4)

Slope formula is

$slope = \frac{y_2-y_1}{x_2-x_1}$

$slope = \frac{4-(-8)}{2-5}$

$slope = \frac{12)}{-3}=-4$

so slope = -4

Slope of any two parallel lines are always equal

Lets find the slope of the equation 13y + kx = 4

Subtract kx on both sides

13 y = -kx + 4

Divide both sides by 13

$y= \frac{-kx}{13} + \frac{4}{13}$

Now slope = -k/13

We know slope of parallel lines are same

So the slope of 13y + kx = 4 is also -4

Hence we equation the slope and find out k

$\frac{-k}{13}=-4$

Multiply by 13 on both sides and divide by -1

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the value of k = 52

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