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givi [52]
2 years ago
12

5x-2y=11 and 3x+4y=4Find the value of x and y in equation.​

Mathematics
2 answers:
nadya68 [22]2 years ago
7 0
  • 5x-3y=11---(1)
  • 3x+4y=4---(2)

(1)×3 and (2)×5

  • 15x-9y=33-(3)
  • 15x+20y=20-(4)

Subtract both

\\ \sf\longmapsto -29y=13

\\ \sf\longmapsto y=\dfrac{-13}{29}

  • Put in eq(1)

\\ \sf\longmapsto 5x+\dfrac{-117}{29}=11

\\ \sf\longmapsto 5x=11+\dfrac{117}{29}=\dfrac{261+117}{29}=\dfrac{278}{29}

\\ \sf\longmapsto x=\dfrac{278}{145}

blagie [28]2 years ago
6 0

Answer:

Step-by-step explanation:

x=2; y=-\frac{1}{2}

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