3 years ago

I need help on problem called irrational numbers

Mathematics

1 answer:

AnnyKZ [126]3 years ago

3 0

Answer:

What is it?

Step-by-step explanation:

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Find the labeled angles

ipn [44]

Answer:

X = 25, Angles are 65 degrees

Step-by-step explanation:

3x-10 = x+40

2x=50

x=25

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3 years ago

Anyone knows the ans it is in the photo question

evablogger [386]

It is 66 times three

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3 years ago

Find the distance between the points. Give an exact answer

never [62]

Answer: $2\sqrt{10} \approx 6.325$

Step-by-step explanation:

$\sqrt{(-9-(-11))^2 +(-3-(-9))^2}=2\sqrt{10} \approx 6.325$

4 0

1 year ago

Can someone plz help me

dangina [55]

Answer:

4j+24k

Step-by-step explanation:

Expand by distributing terms.

4j+4\times 6k

4j+4×6k

2 Simplify 4\times 6k4×6k to 24k24k.

4j+24k

3 0

3 years ago

Write as a product: 25a2−0.01b10

Yakvenalex [24]

Answer:

We conclude that:

$25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$

Step-by-step explanation:

Given the expression

$25a^2-0.01b^{10}$

Rewrite $25a^2-0.01b^{10}$ as $\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2$

$25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2$

Apply difference of two squares formulas:

$x^2-y^2=\left(x+y\right)\left(x-y\right)$

$\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)$

$=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$ ∵ $\sqrt{0.01}=0.1$ ,

Therefore, we conclude that:

$25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$

7 0

2 years ago

I need help on problem called irrational numbers​

I need help on problem called irrational numbers