Hmm well maybe there is bad Bluetooth connection coming from the laptop
Answer:
Follows are the solution to this question:
Explanation:
If Windy needs to study and be a specialist in graphic designing for machines, I'm going to provide a windy link of the machine with such a 64 bit, 3-GHz Intel or AMD processor with an 8 GB RAM, an OpenGL 4.1 chip, an inter-button cursor, a right thumbstick, or a storage drive with GB at least.
- All above description for the computer is suitable for windy because you would well be aware throughout the graphic designing, that may be learned through iRhino 3D (iOS), Autocad, Magical Plan, Morphoio trace, etc if you'd like to graduation in architecture.
- They require fast internet for each application, that can also be installed and installed, that often requires a profile of all technical support programs as well as a web-only storage license.
- As many of the above applies also runs through an AMD or six-bit intel, but not on the ARM processor or instance iRhino 3D (iOS) isn't consistent with an Embedded system, I will select the processor like an Intel or 3GHz AMD processor.
Answer:
numAccounts = SavingsAccount.numberOfAccounts
Explanation:
In object oriented programming, when you have created an object of class, you can create several instances (objects) from that class by referencing the className.classFeild. In this instance SavingsAccount is the class name and
numberOfAccounts is a feild (or data member). to create a new numAccount, we use the syntax as above in the answer
Answer:
While we almost never get to see most of the cables, they power everything so it only makes sense that you should know what the different types of cables and wires are, so that you can pick accordingly and have your equipment, devices and appliances powered properly.
It is also important to identify cables and conductors for safety purposes, such as emergencies linked with electricity.
Answer:
see explaination for program code
Explanation:
scalar_product = 0
li=[]
li2=[]
#reading numbers1.txt and numbers2.txt intoli and li2 respectively
with open('numbers1.txt') as n1, open('numbers2.txt') as n2:
for line1 in n1:
li.append(int(line1))
for line2 in n2:
li2.append(int(line2))
#storing min list size into variable l
a=len(li)
b=len(li2)
if a<b:
l=a
else:
l=b
#calculating scalar product
for i in range(l):
scalar_product=scalar_product+li[i]*li2[i]
print("scalar product is",scalar_product)
