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Stells [14]
3 years ago
9

3x-2y=4 2x+3y=7 X=? Y=? Plz step by step

Mathematics
2 answers:
AysviL [449]3 years ago
4 0

Answer:

x= 2

y= -1

Step-by-step explanation:

Simultanous equation(elimination method)

STEP 1: multiply the number near x with the opposite equation.

in this case in equation 1, three is near x so u multiply it with the second equation.

2(3x-2y=4)

3(2x+3y=7)

you get 6x-4y=8

6x+9y=21

STEP 2: Change the sign ONLY IN SECOND equation to its opposite sign

6x-4y=8 <-------- 1st equation

6x+9y=21 <-------- 2nd equation

SO WE CHANGE THE SIGN IN SECOND EQUATION TO: -6x-9y= -21

STEP 3: Now do the elimination part and calculation

+6x-4y=8

-6x-9y= -21

___________

0x-13y= 13

NOTE: X IS ALWAYS CANCELLED IF ITS NOT THERE'S PROBABLY A MISTAKE

STEP 4: Solve for y

now that x is cancelled we have to solve for y.. to do this take the eliminated equation in step 3 and solve for y

-13y= 13

y= 13/-13

y= -1

STEP 5: We have officially solved for y.. now we need to bother about x.. to solve for x take the first original equation IN THE QUESTION and substitiute( replace) y value in equation

ORIGINAL EQUATION: 3x-2y=4

3x-2(-1)=4

3x-2=4

x= 6/3

x= 2

NOTE: YOU CAN ALSO TAKE THE SECOND EQUATION BUT ITS EASIER WHEN YOU TAKE THE FIRST ONE. EITHER WAY YOU MUST GET THE SAME ANSWER

Elanso [62]3 years ago
4 0

Answer:

x=2, y=1

Step-by-step explanation:

3x-2y=4

2(3x-2y)=2(4)

6x-4y=8

2x+3y=7

3(2x+3y)=3(7)

6x+9y=21

6x+9y-(6x-4y)=21-8

6x+9y-6x+4y=13

13y=13

y=13÷13

=1

3x-2y=4

3x-2(1)=4

3x=4+2

=6

x=6÷3

=2

Hence, x=2 and y=1.

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If f(x) = x2 − x − 12 and g(x) = x2 − 16, find f(x) × g(x).
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Answer:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

Step-by-step explanation:

We have the function f(x) = x^2 − x − 12  and g(x) = x^2 − 16 and we need to find the multiplication of both functions.

f(x) × g(x) = ( x^2 − x − 12)(x^2 − 16) = x^4 - 16x^2 -x^3 + 16x -12x^2 + 192

Simplifying:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

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