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Fudgin [204]
3 years ago
11

If f(x) = x2 − x − 12 and g(x) = x2 − 16, find f(x) × g(x).

Mathematics
2 answers:
Andreyy893 years ago
7 0

Answer:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

Step-by-step explanation:

We have the function f(x) = x^2 − x − 12  and g(x) = x^2 − 16 and we need to find the multiplication of both functions.

f(x) × g(x) = ( x^2 − x − 12)(x^2 − 16) = x^4 - 16x^2 -x^3 + 16x -12x^2 + 192

Simplifying:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

romanna [79]3 years ago
3 0

Answer: f(x)*g(x)=x^4-x^3-28x^2+16x+192

Step-by-step explanation:

Given the function f(x) and g(x):

f(x)=x^2 - x -12\\\\g(x)= x^2 - 16

We need to multiply them. To do this we need to remember the Product of power property, which states:

(a^m)(a^n)=a^{(m+n)}

And the multiplication of signs:

(+)(+)=+\\(+)(-)=-\\(-)(-)=+

Then:

f(x)*g(x)=(x^2 - x -12)(x^2 - 16)\\\\f(x)*g(x)=x^4-16x^2-x^3+16x-12x^2+192

Adding like terms, we get:

f(x)*g(x)=x^4-x^3-28x^2+16x+192

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the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?
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<u>Given</u>:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

<u>General term:</u>

The general term of the geometric sequence is given by

a_n=a(r)^{n-1}

where a is the first term and r is the common ratio.

The 11th term is given is

a_{11}=a(4)^{11-1}

48=a(4)^{10} ------- (1)

The 12th term is given by

192=a(4)^{11} ------- (2)

<u>Value of a:</u>

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

48=a(1048576)

Dividing both sides by 1048576, we get;

\frac{3}{65536}=a

Thus, the value of a is \frac{3}{65536}

<u>Value of the 10th term:</u>

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term a_n=a(r)^{n-1}, we get;

a_{10}=\frac{3}{65536}(4)^{10-1}

a_{10}=\frac{3}{65536}(4)^{9}

a_{10}=\frac{3}{65536}(262144)

a_{10}=\frac{786432}{65536}

a_{10}=12

Thus, the 10th term of the sequence is 12.

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2 years ago
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Answer:

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