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Fudgin [204]
3 years ago
11

If f(x) = x2 − x − 12 and g(x) = x2 − 16, find f(x) × g(x).

Mathematics
2 answers:
Andreyy893 years ago
7 0

Answer:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

Step-by-step explanation:

We have the function f(x) = x^2 − x − 12  and g(x) = x^2 − 16 and we need to find the multiplication of both functions.

f(x) × g(x) = ( x^2 − x − 12)(x^2 − 16) = x^4 - 16x^2 -x^3 + 16x -12x^2 + 192

Simplifying:

f(x) × g(x)= x^4 - x^3 - 28x^2 + 16x + 192

romanna [79]3 years ago
3 0

Answer: f(x)*g(x)=x^4-x^3-28x^2+16x+192

Step-by-step explanation:

Given the function f(x) and g(x):

f(x)=x^2 - x -12\\\\g(x)= x^2 - 16

We need to multiply them. To do this we need to remember the Product of power property, which states:

(a^m)(a^n)=a^{(m+n)}

And the multiplication of signs:

(+)(+)=+\\(+)(-)=-\\(-)(-)=+

Then:

f(x)*g(x)=(x^2 - x -12)(x^2 - 16)\\\\f(x)*g(x)=x^4-16x^2-x^3+16x-12x^2+192

Adding like terms, we get:

f(x)*g(x)=x^4-x^3-28x^2+16x+192

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A ship is sailing on the sea. It travels 50 miles at 60° to the horizontal. Then the ship travels 90 miles at 30° to the horizon
pav-90 [236]

Answer:

(25\sqrt{3}+45)\ miles

Step-by-step explanation:

we know that

The total vertical distance (total miles North) traveled is equal to

d=50sin(60^o)+90sin(30^o)

Remember that

sin(60^o)=\frac{\sqrt{3}}{2}

sin(30^o)=\frac{1}{2}

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4 years ago
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3 years ago
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Pls help with #14 and #15!!!Asap 15 points
inna [77]

Answer:

14. -g + 10, 15. 12k + 3

Step-by-step explanation:

I'm assuming you want to simplify the equation. For 14, we distribute -2. This gets us -2g + 10 + g. We can simplify that to -g + 10. We can't simplify that, so our answer is complete. For 15, we combine 8k and 4k to get 12k + 3. That can't be simplified, so we are done.

8 0
3 years ago
The bases of the trapezoid are 6 and 10. The height is 4. Find the area.
kari74 [83]
<h2>Answer:</h2>

b. \ \boxed{32 \sq. \ units}

<h2>Step-by-step explanation:</h2>

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, b_{1}\,and\,b_{2}. Also, the height H of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of b_{1},b_{2}\:and\:H is:

A=\frac{(b_{1}\text{+}b_{2})h}{2}

Since:

b_{1}=6, \ b_{2}=10, \ and \ H=4

The area is:

A=\frac{(6\text{+}10)4}{2}=\boxed{32 \sq. \ units}

6 0
3 years ago
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