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kakasveta [241]
3 years ago
6

Find the value of 15625 × (-2) + (-15625) × 98

Mathematics
2 answers:
ziro4ka [17]3 years ago
7 0

Answer:

-1562500

Step-by-step explanation:

5625\left(-2\right)+\left(-15625\right)\times \:98

15625\left(-2\right)

=-31250

15625\times \:98

=1531250

-31250-1531250

-1562500

gregori [183]3 years ago
6 0

Answer:

-1562500

Step-by-step explanation:

15625 × (-2) + (-15625) × 98 = -31250 + (-1531250)

                                              = -31250 - 1531250

                                              = -1562500

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A 13foot lader i upagenst a tree the bottom of the ladder is 5 feet away form the tree how high is the ladder on the tree
SCORPION-xisa [38]

Think of the 13-ft length of the ladder as the hypotenuse of a right triangle. Represent the horiz. distance from foot of ladder to base of tree by x, or 5 ft.

Represent the vert. dist. from base of tree to top of ladder by y, which is unknown.


Then (13 ft)^2 = (5 ft)^2 + y^2, or


169 ft^2 = 25 ft^2 + y^2. This simplifies to y^2 = 144. Thus y = + 12 feeet.


Note: Please pay attention to your spelling: "lader i up agenst a tree" should be "the top of a 13-ft ladder is placed against a tree."

7 0
3 years ago
Help me please,Thanks
ehidna [41]
The answer is 1/16 i think. Hope this helps! :)
3 0
3 years ago
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kiruha [24]

Answer:

24 units²

Step-by-step explanation:

Surface area of a cube = 6a² , where a = the side given

=> 6(2)²

=> 6(4)

=> 24 units²

Hope this helps!

4 0
3 years ago
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What is the slope of the following table?
NNADVOKAT [17]

Answer:

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Step-by-step explanation:

6 0
3 years ago
In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m
olasank [31]
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}

The probability is 1/57.
4 0
3 years ago
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