Answer:
Randomly selecting a six of diamonds - 1 / 52
Randomly selecting a 7, 8, 9 or 10 - 4 / 13
Step-by-step explanation:
There is only 1 six of diamonds in a standard deck of cards. There are 52 cards in a deck, thus the probability of pulling a six of diamonds is 1 in 52.
There are 4 of each card in a deck. so they are 4 7's, 4 8's. 4 9's and 4 10's. And there are a total of 52 cards in a deck. So the probability of pulling a 7,8,9 or 10 are 4 + 4 + 4 + 4 in 52
4 + 4 + 4 + 4 = 16
16 / 52 simplified is 4 / 13 Therefore the is a 4 in 13 chance of pulling a 7 8 9 or 10
The other ones are correct
Im not sure i understand the question, but i think 25/7
Answer:
1. (6, 2) and (-3, -6) 2. (-4 and -6) and (3, -8) 3.(-2, -8) and (6, 4) 4.(-3, 9) and (0, 1) 5.(2, -2) and (8, 1) 6.(-12, 4) and (0, 2) 7.(-8, -4) and (4, -7) 8.(-4, 13) and (-2, 6)
Step-by-step explanation:
Answer:
y=28/5
Step-by-step explanation:
Okay so for this we can use cross- multiplication. Basically, the product of the numerator of the first number and the denominator of the second is equal to the product of the denominator of the first and the numerator of the second.
What I mean is: 4*7=5*y
so,
28=5y
y=28/5
You did good, it IS correct.
