C.(x,y) (x-5,y+3) D.(x,y) (x+3,y-5) Geometry math question

Mathematics

2 answers:

laiz [17]3 years ago

8 0

The correct answer is D. (x,y) -> (x + 5,y - 3) because R(-4,0); R'(1,-3); -4 + 5 = 1 and 0 -3 = -3;

stepladder [879]3 years ago

3 0

The correct answer is D. (x,y) -> (x + 5,y - 3) because R(-4,0); R'(1,-3); -4 + 5 = 1 and 0 -3 = -3;

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lilavasa [31]

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$f(x)=\dfrac{x^2+2x-3}{x-7}\\\\vertical\ asymptote:\\\\x-7=0\qquad\text{add 7 to both sides}\\\\\boxed{x=7}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{1-\frac{7}{x}}=\pm\infty\\\\\boxed{not\ exist}$

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