The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:
Differentiate the function with respect to t
Set to 0
So, we have:
Collect like terms
Solve for t
Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
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Answer:
Step-by-step explanation:
8 in × (1 ft)/(12 in) = ⅔ ft
36 ft × 58 ft × ⅔ ft = 1392 ft³
1392 ft³ × (1 yd³)/(27 ft³) ≅ 52 yd³
52 yd³ × $123/yd³ = $6396
To calculate the velocity, we use the given expression above which is <span>s(t) = −16t^2 + 144. First, we calculate the time it takes to reach the ground. Then, differentiate the expression and substitute time to the differentiated expression.
</span>s(t) = −16t^2 + 144
0 = -16t^2 + 144
t = 3
s'(t) = v = -32t
v = -32(3)
v = -96
Note: negative sign signifies that the object is going down
Answer:
15-16=-1
Step-by-step explanation:
Answer:
(-1/2,1/2)
Step-by-step explanation:
Normally for sinx amplitude is 2 (1 +1). In the case when it is half sine amplitude is halved, therefore 0.5 +0.5 = 1 Paramers alpha = 2x does not matter because it only stretches the graph horizontally.
hope it helped
