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Shkiper50 [21]
3 years ago
14

Find the area of a circle whose circumference is 31.4 centimeters. Approximate Π as 3.14.

Mathematics
2 answers:
Rina8888 [55]3 years ago
4 0

Answer:

Area of circle is 78.5 cm²

Step-by-step explanation:

Given: circumference is 31.4 centimeters

We have to find the area of circle.

We know Circumference = 2\pi r

Also given circumference = 31.4

So, Substitute, to find the radius,

31.4=2\pi r

Divide both side by 2π, we have,

\frac{31.4}{2\pi}=r

Also, Area of circle = \pi r^2

Substitute, \frac{31.4}{2\pi}=r , we have,

Area of circle = \pi (\frac{31.4}{2\pi})^2

Simplify, we get,

Area of circle = \pi (\frac{15.7}{\pi})^2

Area of circle = (\frac{(15.7)^2}{\pi})

Put π = 3.14 , we get,

Area of circle = 78.5  centimeter²

Thus, Area of circle is 78.5 cm²

yaroslaw [1]3 years ago
3 0
Circumference = 2(3.14)r
31.4=2(3.14)(r)
Radius=5

Area=3.14(5^2)
A=78.5
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Match each function to its corresponding sequence.
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The sequence and their functions are:

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  • f(n) = 2[f(n - 1)] ⇒ 3, 6, 12, 24, 48.....

<h3>How to match the functions?</h3>

To do this, we simply set values for n and calculate the function values using the current value of n.

So, we have:

<u>Function 1: f(n) = f(n - 1) + 6n - 5 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 6(2) - 5 = 3 + 12 - 5 = 10

Let n = 3

f(3) = f(2) + 6(3) - 5 = 10 + 18 - 5 = 23

None of the sequence follows the pattern 3, 10, 23....

<u>Function 2: f(n) = f(n - 1) + 2n - 1 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 2(2) - 1 = 3 + 4 - 1 = 6

Let n = 3

f(3) = f(2) + 2(3) - 1 = 6 + 6 - 1 = 11

None of the sequence follows the pattern 3, 6, 11....

<u>Function 3: f(n) = f(n - 1) + 6 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 6 = 3 + 6 = 9

Let n = 3

f(3) = f(2) + 6 = 9 + 6 = 15

None of the sequence follows the pattern 3, 9, 15....

<u>Function 4: f(n) = f(n - 1) + 7 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 7 = 3 + 7 = 10

Let n = 3, 4 and 5

f(3) = f(2) + 7 = 10 + 7 = 17

f(4) = f(3) + 7 = 17 + 7 = 24

f(5) = f(4) + 7 = 24 + 7 = 31

So, we have:

f(n) = f(n - 1) + 7 ⇒ 3, 10, 17, 24, 31.....

<u>Function 5: f(n) = f(n - 1) + 4n - 2 where f(1) = 3</u>

Let n = 2

f(2) = f(1) + 4(2) - 2 = 3 + 8 - 2 = 9

Let n = 3, 4 and 5

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f(5) = f(4) + 4(5) - 2 = 33 + 20 - 2 = 51

So, we have:

f(n) = f(n - 1) + 4n - 2 ⇒ 3, 9, 19, 33, 51.....

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Let n = 2

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Let n = 3, 4 and 5

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f(4) = 2 * f(3) = 2 * 12 = 24

f(5) = 2 * f(4) = 2 * 24 = 48

So, we have:

f(n) = 2[f(n - 1)] ⇒ 3, 6, 12, 24, 48.....

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brainly.com/question/6561461

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Answer:

The answer is below

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