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mart [117]
3 years ago
13

A box contains 12 cards numbered from 1 to 12 and 7 face cards. Two cards are randomly drawn from the box without replacement. F

ind the probability P(an even number and a face card)
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

Answer:

i think it is 1/2, or 50%

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Dan drew the line of best fit on the scatter plot shown below: A graph is shown with scale along x axis from 0 to 10 at incremen
Anit [1.1K]
     0, 3
-   10, 15
= -10, -12
therefore, the slope is 6/5, and the intercept (c) is as supplied, 3.
the equation, y=mx+c or y = a + bx, can be applied here where m or b = 6/5, and a or c = 3.

therefore the equation is y=6/5x+3.

To test this, you can put in y = 10(6/5)+3, which spits out y = 15. This way we know it *should* work.

3 0
3 years ago
Simplifying the following expression:<br> 6x + 2(3x + 5) + (-9)
Nezavi [6.7K]
= <span>6x + 2(3x + 5) + (-9)
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In short, Your Final Answer would be 12x + 1

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3 0
3 years ago
Read 2 more answers
Which equation represents an exponential function with an initial value of 500? f(x) = 100(5)x f(x) = 100(x)5 f(x) = 500(2)x f(x
Evgen [1.6K]

Answer:

The answer is

Step-by-step explanation:

C. f(x) = 500(2)^x

2020

3 0
3 years ago
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Does anyone know this
Rudik [331]

Answer:

its the first one. you're right.

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6 0
2 years ago
When the outliers are removed, how does the mean change? (2 points) dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1
777dan777 [17]

Answer:

Answer: The mean increases by 3

Step-by-step explanation:

The original data set is 

{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}

The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.

The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77

If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80

So in summary so far

old mean = M = 77

new mean = N = 80

The difference in values is N-M = 80-77 = 3

So that's why the mean increases by 3

8 0
3 years ago
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