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Andreas93 [3]
3 years ago
12

Find the slope of the line y=5x-4

Mathematics
2 answers:
butalik [34]3 years ago
8 0

Answer:

its 5

Step-by-step explanation:

with a y intercept of -4

Effectus [21]3 years ago
7 0
The slope of y = 5x - 4 is 5.
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Re-write the equation 3x - y = 4 in slope-intercept form.
Verdich [7]

Answer:

a

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Rearrange 3x - y = 4 into this form ( add y to both sides )

3x = y + 4 ( subtract 4 from both sides )

3x - 4 = y OR y = 3x - 4 → a

5 0
3 years ago
Help? Please. Thanks???
Naya [18.7K]

The height is represented by d.

d = 10 feet

10 = -  16 {t}^{2}  - 7t + 61 \\ 0 =  - 16 {t}^{2}  - 7t + 51

Use quadratic formula:

t = 1.58, -2.02 (reject)

1.58 seconds

3 0
3 years ago
What is the value of q − 7 if q = −17?
sdas [7]

Answer:

-24

Step-by-step explanation:

-7 - 17 = -24.

3 0
1 year ago
Read 2 more answers
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

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3 years ago
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