Answer: y = x/2 + 3
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m = change in value of y on the vertical axis / change in value of x on the horizontal axis
change in the value of y = y2 - y1
Change in value of x = x2 -x1
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
Looking at the graph,
y2 = 6
y1 = 4
x2 = 6
x1 = 2
Slope,m = (6 - 4)/(6 - 2) = 2/4 = 1/2
To determine the intercept, we would substitute x = 2, y = 4 and m= 1/2 into y = mx + c. It becomes
4 = 1/2 × 2 + c
4 = 1 + c
c = 4 - 1
c = 3
The equation becomes
y = x/2 + 3
Hey there!
10(a - 2.5 + 0.56b)
= 10(a) + 10(-2.5) + 10(0.56b)
= 10a - 25 + 5.6b
= 10a + 5.6b - 25
Therefore, your answer is: 10a + 5.6b - 25
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
x=2
1:Subtract 2x from both sides.
2:Combine 2/3 x and -2x to get -4/3
3:Subtract 3/8 from both sides. Anything subtracted from zero gives its negation.
4:Multiply both sides by -3/4,the reciprocal of -4/3
5:Multiply − 3/8 times − 4/ 3 by multiplying numerator times numerator and denominator times denominator.
6:Do the multiplications in the fraction −8(−3) over 3x4.
x=24/12
Divide 24 by 12 to get 2.
x=2
The point would be on the -2.
The range of any graph are the set of all the y-values of the graph. For this graph, it goes all the way from 0 to about 3.5. I'd say the range of this graph was {0, 3.5}. Hope I could help!
