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3 years ago

If g(x) =x^2 + 1, find g(4)

Mathematics

1 answer:

Papessa [141]3 years ago

4 0

Answer:

Step-by-step explanation:

Since we are evaluating g(x) for g(4), we would substitute x in the equation with 4.

x² + 1

(4)²+ 1

16 + 1

I hope this helps

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Suppose y varies directly with x. Write a direct variation equation that relates x and y. Then find the value of y when x=12

kati45 [8]

So x= 3, y= 7

3/7 = 12/21

Which number times 3 is equal 12
3(4) = 12
So 7(4) = 28

X= 12 , y= 28

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3 years ago

What is .0449 rounded to the nearest hundredth?

elena-14-01-66 [18.8K]

I believe that it's .04

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3 years ago

Someone please helppp

mel-nik [20]

Answer:

k = 5/6

Step-by-step explanation:

First, we can make this have the form of a quadratic function, or ax²+bx+c=0. To do this, we can first subtract 10x from both sides to get

(2k+1)x²-8x=-6

Next, we can add 6 to both sides, resulting in

(2k+1)x²-8x+6 = 0

For a quadratic function of form ax²+bx+c=0, we can see that a=2k+1, b=-8, and c=6. We can then apply the quadratic equation, or

x= (-b ± √(b²-4ac))/(2a) to get our roots to be

x= (8 ± √(64-4(6)(2k+1)))/(2*(2k+1))

= (8 ± √(64-(48k+24)))/(4k+2)

= (8 ± √(40-48k))/(4k+2)

For the roots to be equal, we must have the two roots equal to each other. We can write this as

(8 + √(40-48k))/(4k+2) = (8 - √(40-48k))/(4k+2)

multiply both sides by (4k+2) to remove the denominator

8+√(40-48k) = 8 - √(40-48k)

subtract 8 from both sides to isolate the square roots

√(40-48k) = - √(40-48k)

The only number that is equal to its negative self (and is real) is 0. Therefore, √(40-48k) = - √(40-48k) = 0, so we have

√(40-48k) = 0

square both sides to remove the square root

40-48k = 0

add 48k to both sides to isolate the k and its coefficient

40 = 48k

divide both sides by 48 to isolate k

k = 40/48 = 5/6

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3 years ago

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Nadusha1986 [10]

We can eliminate choice C because our parabola is not upside down. The way I determined which one it was was by picking a point on the graph and testing the x value of the point in the equation. If the y value on the graph was the same as the y value on my calculator, then I chose the right one. Let me give you an example of what doesn't work first. Let's pick (3, 2) from the graph. Let's test that point in choice D. Filling in x = 3, y should = 2 if that's the right equation. $\frac{1}{2}(3^2)-3+2= \frac{7}{2}$ . Our y coordinate is not 7/2, it's 2. Let's try A: $\frac{1}{3}(3^2)-3-2=-2$ . Again, our y value is 2, not -2. Let's try B: $\frac{1}{3}(3^2)-3+2=2$ . See how that works? Your choice is B.

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3 years ago

Negative 3 over 1 third plus 8 over 3 tenths

Katen [24]

The answer to your question is 7/5

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3 years ago