All the points that are 6 units from (-1, 1) are those on the circle
(x+1)^2 +(y-1)^2 = 36
For y=0, the two points of interest satisfy
(x+1)^2 +1 = 36
(x+1)^2 = 35 . . . . . . subtract 1
x+1 = ±√35
x = -1±√35
The points you seek are
(-1-√35, 0) and (-1+√35, 0), about (-6.916, 0) and (4.916, 0).
Background: log (a . b) = log a + log b
hence log(10000x) = log 10000 + log x but we know that log 10000 = 4
= 4 + log x
therefore the graph of log(10000x) is just the graph of log x transposed by 4
Answer:
The arc measure, x, that the satellite can see is 160°
Step-by-step explanation:
Given that the two tangents intersect at a point outside the with circle center O
The angle formed between between the two tangent = 20°
The first arc formed is measured as x°, which is the arc opposite the point where the two tangents meet = The arc the satellite can see
The angle x is given by the relationship;
x = 2 × (90 - v/2)
Where;
v = The angle formed at the point where the two tangent meet = 20°
Therefore;
x = 2 × (90 - 20/2) = 2 × (90 - 10) = 2 × 80 = 160°
The arc measure, x, that the satellite can see = 160°.
<u>Answer:</u>
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<u>Step-by-step explanation:</u>
To find the area of a rectangle, we have to multiply the length with the width.
In the question, the given length is 'x' and the width given is 'x +7'
So, the area would be
( ) x ( )
The area = 
So, the equation to find the area of such a rectangle would be:-
( ) x ( )
