The total surface area of the remaining solid is 48(4+✓3) centimeters square.
<h3>How to calculate the surface area?</h3>
Through a regular hexagonal prism whose base edge is 8 cm and the height is 12 cm, a hole in the shape of a right prism.
The formula for the total surface area will be:
= Total surface area=2(area of the base)+ parameter of base × height
where,
Height= 8cm
Parameter of base=12(2) = 24
Area of the base= 6×✓3/4×4² = 64✓3/4
The surface area of the remaining solid will be:
= 2(64✓3/4) + 24 × 8
= 2(64✓3/4 + 192
With the hole is a rhombus prism with the following parameters:
diagonal 1 = 6, diagonal 2 = 8, height = 12
The volume is:
V1 =0.5 × d1 × d2 × h
V1 = 0.5 × 6 × 8 × 12
V1 = 96
The dimensions of the hexagonal prism are:
Base edge (a) = 8
Height (h) = 12
The volume is
V2 = (3✓(3)/2)a²h
V2 = (3✓3)/2) × 8² × 12
V2 = 1152✓3
The remaining volume is
V = V2 -V1
V = 1152✓3 - 96
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Answer:
D
Step-by-step explanation:
-10° C is the lowest temperature and 7°C is the highest temperature.
14. 6.4 blocks
15. 1.78
16. 7.47
Answer:
3025
Step-by-step explanation:
let's look at it in this concept.
For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.
LCM of 11 and 5=55
therefore the number is 55x, where x is a positive integer.
it is a said that the number is a perfect square
therefore the square root of 55x must be an integer.

the smallest value of x to make 55x a perfect square is....

Therefore the number is.... .

<em>sweet</em><em> </em><em>right</em>
<h2>
<u>B</u><u>R</u><u>A</u><u>I</u><u>N</u><u>L</u><u>I</u><u>E</u><u>S</u><u>T</u><u> </u><u>P</u><u>L</u><u>S</u><u>.</u><u>.</u><u>.</u><u>.</u></h2>
A. 1/5k - 2/3j and -2/3j + 1/5k
Step-by-step explanation:
Equivalent expressions are expressions that are the same even though they may appear different.When you plug in a value to represent a variable in these expression, they will give same answer when simplified.
In
1/5k - 2/3j and -2/3j + 1/5k you notice the operation signs in the terms has been maintained though the position of the terms shifted.
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Keywords: expressions, equivalent
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