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2 years ago

Arrange the given numbers in descending order 4/5,0.09,4,9,2/4

Mathematics

2 answers:

egoroff_w [7]2 years ago

5 0

Answer:

9,4,4/5,2/4,0.09

Step-by-step explanation:

Simple, countdown from 9.

Rufina [12.5K]2 years ago

4 0

Answer:

The descending order is 9, 4, 4/5, 2/4, 0.09

Step-by-step explanation:

Consider the provided numbers.

First convert all the numbers into decimal form as shown:

$\frac{4}{5} =0.8$ , 0.09, 4, 9, $\frac{2}{4} =0.5$

Now we need to arrange them in descending order.

The greatest number among them is 9.

After that the 2nd greatest number is 4 then 0.8, 0.5 and the smallest number is 0.09

Thus, the descending order is 9, 4, 4/5, 2/4, 0.09

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Karen spends $450 on monthly bills. Of this total amount, 12% is for phone service, 1/10 is for internet service, and 2/9 is for

finlep [7]

12%= 0.12 = 12/100 = 108/900
1/10 = 90/900
2/9 = 200/900

108/900 + 90/900 + 200/900 = 398/900 used

900- 398 = 502

502/900 = 251/ 450

251/450 × 450 = 251

Karen has $251 for food

4 0

2 years ago

Urgent pls hlppppp. Multiple choice. Will give brainliest

Dimas [21]

Answer:

The third option

Step-by-step explanation:

This is because you multiply the variable cost (9), by the amount they make, which is x.

7 0

1 year ago

Prove that the product of a nonzero rational number together with an irrational number is an irrational number.

melamori03 [73]

Each time they assume the sum is rational; however, upon rearranging the terms of their equation, they get a contradiction (that an irrational number is equal to a rational number). Since the assumption that the sum of a rational and irrational number is rationalleads to a contradiction, the sum must be irrational.

7 0

3 years ago

Classify the sequence arithmetic , geometric, or neither

Feliz [49]

Answer:

Geometric

Step-by-step explanation:

Given terms are {3, -1, 1/3, -1/9............}

If we have common difference between the terms then it is arithmetic

If we have common ratio between the terms then it is Geometric

Difference of 3 and -1 is 4

Difference of 1/3 and -1 is -4/3

Common difference it not same so it is not Arithmetic

Now we check common ratio

we divide second term by first term

first term is 3 and second term is -1

$\frac{-1}{3}$

now we check with next two terms

$\frac{\frac{1}{3}}{-1}=\frac{-1}{3}$

common ratio is -1/3

So this is Geometric

8 0

3 years ago

Read 2 more answers

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

2 years ago