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Elina [12.6K]
3 years ago
11

Arrange the given numbers in descending order 4/5,0.09,4,9,2/4

Mathematics
2 answers:
egoroff_w [7]3 years ago
5 0

Answer:

9,4,4/5,2/4,0.09

Step-by-step explanation:

Simple, countdown from 9.

Rufina [12.5K]3 years ago
4 0

Answer:

The descending order is 9, 4, 4/5, 2/4, 0.09

Step-by-step explanation:

Consider the provided numbers.

First convert all the numbers into decimal form as shown:

\frac{4}{5} =0.8, 0.09, 4, 9, \frac{2}{4} =0.5

Now we need to arrange them in descending order.

The greatest number among them is 9.

After that the 2nd greatest number is 4 then 0.8, 0.5 and the smallest number is 0.09

Thus, the descending order is  9, 4, 4/5, 2/4, 0.09

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3 ½ x 2/5 *
ki77a [65]

Answer:

Step-by-step explanation:

3\frac{1}{2}=\frac{(3*2)+1}{2}=\frac{7}{2}\\\\\\3\frac{1}{2}*\frac{2}{5}=\frac{7}{2}*\frac{2}{5}=\frac{14}{10}

4 0
2 years ago
I don't understand the question.<br><br>How do I work and answer it ?!!
gavmur [86]
I think its 32 minus 16 which is 16, dont forget to label!
3 0
3 years ago
A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school
nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let p_1 = <u><em>proportion of Illinois high school freshmen who have used anabolic steroids.</em></u>

p_2 = <u><em>proportion of Illinois high school seniors who have used anabolic steroids.</em></u>

SO, Null Hypothesis, H_0 : p_1=p_2      {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, H_A : p_1\neq p_2      {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here <u>Two-sample z test for</u> <u>proportions</u>;

                        T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of high school freshmen who have used anabolic steroids = \frac{34}{1679} = 0.0203

\hat p_2 = sample proportion of high school seniors who have used anabolic steroids = \frac{24}{1366} = 0.0176

n_1 = sample of high school freshmen = 1679

n_2 = sample of high school seniors = 1366

So, <u><em>the test statistics</em></u>  =  \frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }

                                     =  0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0
3 years ago
Hey you!!!! <br> Help me please
gizmo_the_mogwai [7]

Answer:

If the population has increased by 12% then to ensure a generated maximum capacity must be more than 12% we already have a figure being 100% prior so the answer is 12% population increase =112% and 12%.of 112 =13.44

We add this to 12

12+13.44= 25.44

Step-by-step explanation:

3 0
2 years ago
(Q2) Determine the eccentricity, the type of conic, and the directrix for r = 9/1+cos theta
g100num [7]

Answer:

The answer is (d) ⇒ eccentricity = 6 , hyperbola , directrix  x = 3/2

Step-by-step explanation:

∵ r = ek/(1 ± ecosФ)

∵ r = 9/(1 + 6cosФ)

∴ e = 6 ⇒ eccentricity = 6

∵ e > 1

∴ The conic is hyperbola

∵ ek = 9

∴ k = 9/6 = 3/2

∴ The directrix  x = 3/2

3 0
3 years ago
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