The graph of an equation has a minimum y value of 12. This minimum occurs at an x value of 3. What is true of the graph of the e
1 answer:
You might be interested in
Total number of marbles:
75 + 50 + 100 + 25 = 250
Probability of selecting a red marble:
25/250 (since 25 out of 250 marbles are red)
Since the top and bottom of this fraction are both divisible by 25, we can go ahead and divide them both by 25, simplifying to 1/10.
Probability of selecting a green marble:
50/250
Simplifies to 2/10
Simplifies to 1/5.
Probability of selecting a blue or orange marble
(75+100)/250
175/250
Simplifies to 7/10.
To find the probability that each event occurs in order, simply multiply them all together.
75 + 50 + 100 + 25 = 250
Probability of selecting a red marble:
25/250 (since 25 out of 250 marbles are red)
Since the top and bottom of this fraction are both divisible by 25, we can go ahead and divide them both by 25, simplifying to 1/10.
Probability of selecting a green marble:
50/250
Simplifies to 2/10
Simplifies to 1/5.
Probability of selecting a blue or orange marble
(75+100)/250
175/250
Simplifies to 7/10.
To find the probability that each event occurs in order, simply multiply them all together.
Answer:
The farmer have at first <u>202</u> chickens.
Step-by-step explanation:
Given:
A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.
Now, to find the chickens farmer have at first.
Let the chickens be
And, the ducks be
<em>As, the farmer had twice as many chickens as ducks on his farm.</em>
So, ......(1)
<em>As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.</em>
According to question:
Substituting the value of from equation (1) we get:
<em>By cross multiplying we get:</em>
<em>Adding both sides 332 we get:</em>
<em>Subtracting both sides by </em><em> we get:</em>
<em>Dividing both sides by 3 we get:</em>
Now, to get the number of chickens substituting the value of in equation (1):
Therefore, the farmer have at first 202 chickens.