Answer:
The p-value of the test statistic from the standard normal table is 0.0017 which is less than the level of significance therefore, the null hypothesis would be rejected and it can be concluded that there is sufficient evidence to support the claim that less than 20% of the pumps are inaccurate.
Step-by-step explanation:
Here, 1304 gas pumps were not pumping accurately and 5689 pumps were accurate.
x = 1304, n = 1304 + 5689 = 6993
The level of significance = 0.01
The sample proportion of pump which is not pumping accurately can be calculated as,
The claim is that the industry representative less than 20% of the pumps are inaccurate.
The hypothesis can be constructed as:
H0: p = 0.20
H1: p < 0.20
The one-sample proportion Z test will be used.
The test statistic value can be obtained as:

Step 1: Simplify both sides of the equation.
2
−
3
(
2
x
−
1
)
=
−
6
x
+
5
2
+
(
−
3
)
(
2
x
)
+
(
−
3
)
(
−
1
)
=
−
6
x
+
5
(Distribute)
2
+
−
6
x
+
3
=
−
6
x
+
5
(
−
6
x
)
+
(
2
+
3
)
=
−
6
x
+
5
(Combine Like Terms)
−
6
x
+
5
=
−
6
x
+
5
−
6
x
+
5
=
−
6
x
+
5
Step 2: Add 6x to both sides.
−
6
x
+
5
+
6
x
=
−
6
x
+
5
+
6
x
5
=
5
Step 3: Subtract 5 from both sides.
5
−
5
=
5
−
5
0
=
0
It's 2 sir/ Maam Your Welcome
Answer: 
Step-by-step explanation:
The confidence interval for population mean is given by :-

, where
is the sample proportion, n is the sample size ,
is the critical z-value.
Given : Significance level : 
Sample size : n= 85
Critical value : 
Sample proportion: 
Now, the 99% confidence level will be :

Hence, the 99% confidence interval estimate of the true proportion of families who own at least one DVD player is 