Check the picture below. You can pretty much just count the units off the grid.
I Am Going Ask My teacher. I just screenshot it.
The function
f(x) is even
g(x) is neither even nor odd
h(x) is odd
Steps:
for an even function it holds that f(-x) = f(x):
f(-x) = (-1)^6 x^6 - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even
for an odd h(x) it holds that h(-x) = -h(x):
It is easy to show that g(x) does not match any of the two possibilities above.
Step-by-step explanation:
5x-(x+3)=1/3(9x+18)-5
5x-x+3=3x+6-5
1/3 multiplied by 9/1 is three because if you take away the ones and put your problem like this: 9/3, you'll get 3.
1/3 multiplied by 18/1 is six because if you take away the ones and switch to division, it'll look like this: 18/3. 18/3 is 6.
5x-1x+3=3x+6-5
If a variable is alone, you should - in this case - put a one before it, but if the variable is alone you should know that it's automatically a one.
4x+3=3x-1
6-5=1 Simple math problem, probably self explanatory
4x+3=3x-1
Subtract 3x from 4x and you'll get 1x because 4-3 is 1.
1x+3=-1
Then you add 3 to -1 which is 2.
The answer is 1x=2
Or you could've done:
4x+3=3x-1
-4x -4x
3=-1x-1
+-1 +-1
2=1x
It's the same answer, but all I did was subtract the 4x from the 4x and 3x.
