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rewona [7]
3 years ago
7

Write the untis of following physical quantities electric current , force, frequency, density​

Physics
2 answers:
stepan [7]3 years ago
5 0

Answer:

The unit of electric current is Amper.

The unit of force is Newton.

The unit of frequency is Hertz.

The unit of density is kilogram per cubic metre.

Shtirlitz [24]3 years ago
4 0

Answer:

1) electric current - ampere

2) force - joule

3 frequency - hertz

4) density - kilogram per cubic metre

pls follow me friends ..

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Supply the missing force necessary to achieve equilibrium. Show your work.
Mumz [18]

<u>Analysing the Question:</u>

We know that equilibrium is the state of a body when it has equal and opposite forces being applied on it

In this case, a net downward force of 496N is being applied and a net upward force of (106 + 106 + 142 + x) N

<u>Finding the missing force:</u>

Since we have to achieve equilibrium, the net upward forces have to be equal to the net downward forces

So,  (106 + 106 + 142 + x) = 496

354 + x = 496

x = 496 - 354

x = 142 N

Therefore, the missing force is 142 N

8 0
3 years ago
Agent Bond is standing on a bridge, 17 m above the road below, and his pursuers are getting too close for comfort. He spots a fl
faust18 [17]

Answer:

2 poles

Explanation:

We are told Agent Bond is standing on a bridge, 17 m above the road below.

Now, the bed of the truck is 1.5 m above the road.

It means the distance hewill need to fall = 17 - 1.5 = 15.5 m

acceleration due to gravity = 9.8 m/s²

Initial velocity = 0 m/s

Thus, to find the time, we will use the equation;

s = ut + ½at²

Plugging in the relevant values gives;

15.5 = 0 + ½9.8t²

Multiply through by 2 to give;

15.5 × 2 = 9.8t²

31 = 9.8t²

t² = 31/9.8

t = √(31/9.8)

t = 1.78 sec

We are told that he spots a flatbed truck approaching at 28 m/s and that the telephone poles are 22m apart.

Thus; The truck will pass the poles at a rate of; Velocity/distance between poles = 28/22 = 1.273 poles per second

Since, we got the time to be 1.78 seconds, then we can find the number of poles by multiplying it with the rate of poles per seconds.

Thus;

Number of poles = 1.78 second × 1.273 poles/ seconds = 2.27 poles

This is approximately 2 poles

6 0
3 years ago
Can someone help me out?
Sphinxa [80]

Answer:

1) The car is slowing down

2) A = 40N forward & B = 25N up

Explanation:

Whenever you're dealing with forces on moving objects, it is important to look at each of the numbers and the directions they're going in.

With the racecar, we see it has four forces on it, 2,000 N up and down, 8,000 back, and 6,000 N forward. Now, each of these forces are going in their respective directions, but they are most in comparison with the force going in the opposite direction (vertical axis, horizontal axis). The two 2,000 N forces will cancel each other out since there is an equal force in both directions, causing a net force of <u>0 N on the vertical axis</u>. This is because the car is most likely moving on a flat surface. As for the horizontal axis, we simply subtract 6,000 & 8,000 to get a net force of <u>-2,000 N in the backwards direction</u>, telling us that the car is slowing down.

As for the boxes, we see the same vertical and horizontal axes, but separated to each box. Box A has a net force of <u>40 N in the forward direction</u> and Box B has a net force of <u>25 N in the upward direction</u>.

4 0
3 years ago
A satellite is in circular orbit around the earth. The orbit the satellite is at a height of 420 km above the earth's surface. F
astraxan [27]

Answer:

7661.06 m/s

Explanation:

R = Radius of Earth = 6.38\times 10^6\ m

h = Distance from the Earth = 420000 m

G = Gravitational constant = 6.674\times 10^{-11} N m^2/kg^2

M = Mass of Earth = 5.98\times 10^{24}\ kg

V=\sqrt{g{\frac{R^2}{R + h}}}\\\Rightarrow V=\sqrt{\frac{GM}{R^2}{\frac{R^2}{R + h}}}\\\Rightarrow V=\sqrt{\frac{6.674\times 10^{-11}\times 5.98\times 10^{24}}{(6.38\times 10^6)^2}{\frac{(6.38\times 10^6)^2}{6.38\times 10^6 + 420000}}}\\\Rightarrow V=7661.06\ m/s

The orbital speed of the satellite is 7661.06 m/s

6 0
4 years ago
An object moves with simple harmonic motion. If the amplitude and the period are both doubled, the object's maximum speed is 1.
Kisachek [45]

Answer:

The object's maximum speed remains unchanged.

Explanation:

The speed of a particle in SHM is given by :

v(t)=A\omega\ sin(\omega t)

Maximum speed is, v_{max}=A\omega

If A' = 2A and T' = 2T

v'_{max}=(2A)\dfrac{2\pi}{2T}

v'_{max}=(A)\dfrac{2\pi}{T}

v'_{max}=v_{max}

So, the maximum speed of the object remains the same i.e. it remains unchanged. Hence, this is the required solution.

6 0
3 years ago
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