Answer:
3.91
Explanation:
Given that
Final reading of the voltmeter, V2 = 45 v
Initial reading of the voltmeter, V1 = 11.5 v
The dielectric constant k, of a material is usually given as
k = V2/V1
k = 45 / 11.5
k = 3.91
Therefore, the dielectric constant of the material as we've calculated above is sure to be 3.91.
I hope that helps you understand
Well both ends of the magnet have a diffrent magnetic force. i hope this was the answer you where looking for, and have a nice rest of the day
Answer:
The magnitude of the average induced emf is 90V
Explanation:
Given;
area of the square coil, A = 0.4 m²
number of turns, N = 15 turns
magnitude of the magnetic field, B = 0.75 T
time of change of magnetic field, t = 0.05 s
The magnitude of the average induced emf is given by;
E = -NAB/t
E = -(15 x 0.4 x 0.75) / 0.05
E = -90 V
|E| = 90 V
Therefore, the magnitude of the average induced emf is 90V
Rutherford tested Thomson'shypothesis by devising his "gold foil" experiment. Rutherford was forced to discard the Plum Pudding modeland reasoned that the only way the alpha particles could be deflected backwards was if most of the mass in an atom was concentrated in a nucleus.
Answer:
80.33F
Explanation:
(300-273.15)*9/5+32=80.33
