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scoray [572]
3 years ago
5

1) The unit of power is

Physics
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

1) the unit of power is A.Watt

2)100J=50W

100=50s

divide both sides by 50s

S=2s(A)

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Why are common measurement systems important
kenny6666 [7]
So that international people don't mistake units for others. ex 1 inch could be mistaken for 1 cm in non American countries
6 0
3 years ago
A child tugs on a rope attached to a 0.62 kg toy with a horizontal force of 16.3 N. A puppy pulls the toy in the opposite direct
sattari [20]

Answer:

a=51.77\ m/s^2

Explanation:

Given that,

The mass of a toy, m = 0.62 kg

Force with which a child pull the toy = 16.3 N

The force with which the toy pulled in the opposite direction = -15.8 N

We need to find the acceleration of the toy. Let F be the net force acting on the toy. It is equal to :

F = 16.3 N - (-15.8 N)

= 32.1 N

Let a be the acceleration of the toy. Using Newton' second law of motion to find it.

F = ma

a=\dfrac{F}{m}\\\\a=\dfrac{32.1}{0.62}\\\\a=51.77\ m/s^2

So, the acceleration of the toy is 51.77\ m/s^2.

5 0
3 years ago
A student hears a police siren. What would change the frequency that the student hears? check all that apply
andriy [413]

Considering the Doppler efect, the frequency heard by the student would change if:

  • if the student walked toward the police car.
  • if the student walked away from the police car.
  • if the police car moved toward the student.
  • if the police car moved away from the student.

<h3>Doppler effect</h3>

The Doppler effect is defined as the change in the apparent frequency of a wave produced by the relative motion of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

f'=f\frac{v+-vR}{v-+vE}

Where:

  • f', f: Frequency perceived by the receiver and frequency emitted by the transmitter, respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)
  • v: Wave propagation speed in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 343 m/s.
  • vR, vE: Receiver and transmitter speed respectively. Its unit of measure in the S.I. is the m/s
  • ±, ∓:
  • We will use the + sign:
  1. In the numerator if the receiver approaches the sender
  2. In the denominator if the sender moves away from the receiver
  • We will use the - sign:
  1. In the numerator if the receiver moves away from the sender
  2. In the denominator if the sender approaches the receiver

In summary, the Doppler Effect is an alteration of the observed frequency of a sound due to the movement of the source or the observer, that is, they are changes in the frequency and wavelength of a wave due to the relative movement between the wave source and the observer.

<h3>Changes on the frequency </h3>

In this case, considering the Doppler effect, the frequency heard by the student would change if:

  • if the student walked toward the police car.
  • if the student walked away from the police car.
  • if the police car moved toward the student.
  • if the police car moved away from the student.

Learn more about Doppler effect:

brainly.com/question/15307081

brainly.com/question/4052291

brainly.com/question/15097772

brainly.com/question/3841958

#SPJ12

7 0
2 years ago
What is the elastic potential energy of a spring that is compressed a distance of 0.35 m and has a spring constant of 71.8 N/m?
Vitek1552 [10]

Answer:

P.E = 4.398 Joules.

Explanation:

Given the following data;

Spring constant, k = 71.8N/m

Displacement, x = 0.35m

To find the elastic potential energy;

The elastic potential energy of an object is given by the formula;

P.E = \frac {1}{2}kx^{2}

Substituting into the equation, we have;

P.E = \frac {1}{2}*71.8 *(0.35)^{2}

P.E = 35.9 * 0.1225

Elastic potential energy = 4.398 Joules.

<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>

3 0
3 years ago
Explain what is happening in this<br> induction example.
Semmy [17]

Answer:

An electrical field duh

Explanation:

None needed self explanitory

4 0
2 years ago
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