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Delvig [45]
3 years ago
8

Can someone plz help me

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:

C

Step-by-step explanation:

It makes sense

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Factor completely. y2+6y+8
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If you can't see the picture the answer is: (y+4)(y+2).

Hope this helps, and May the Force Be With You!
-Jabba

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3 years ago
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5 The area of a rectangular lawn is 255 m². If its length is 15 m, find its perimeter.​
Marina CMI [18]
Area of a rectangular lawn = l×b

255=15×x

Hence the breadth is 17 m

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3 years ago
24. What are the x and y intercepts of the following
Mila [183]

Answer:

C

A. X-intercept (6,0) and y-intercept (0,-8) wrong

B. x-intercept (-8,0) and y-intercept (0,6)wrong

C. x-intercept (4,0) and y-intercept (0,-3) correct

D. x-intercept (-3,0) and y-intercept (0,4) wrong

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Tema [17]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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