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2 years ago

12

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1 answer:

vesna_86 [32]2 years ago

8 0

Answer:

Step-by-step explanation:

three angles measuring 75°, 45°, and 60°

75+45+60 = 180 -> can create triangle

three sides measuring 7 m, 10 m, and<u> lym (assume this is 16) </u>

satisfy this a-b<c<a+b -> can create triangle

three angles measuring 40°, 50%, and 60°

40+50+60 = 150 ≠ 180 -> cannot create triangle

three sides measuring 3 cm, 4 cm, and 5 cm

satisfy this a-b<c<a+b -> can create triangle

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2 years ago

From an industrial area 70 companies were selected at random and 45 of them were panning for expansion next year. Find 95% confi

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Confidence limit = [52.8%, 75.2%]

Step-by-step explanation:

$P=\frac{45}{70}= 0.64$

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2 years ago

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2 years ago

Read 2 more answers

A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

5 0

2 years ago