Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
Answer: 5 and 6
Step-by-step explanation:
sqrt1=1
sqrt4=2
sqrt9=3
sqrt16=4
sqrt25=5
sqrt29~5.4
sqrt36=6
Answer: y = 3x^2 -x + 2
Step-by-step explanation:
Answer: 5.875 miles run on Friday to reach her goal by Jen
Step-by-step explanation:
Since we have given that
Part of distance covered on Monday by Jen is given by

Part of distance covered on Tuesday by Jen is given by

Part of distance covered on Wednesday by Jen is given by
0
Part of distance covered on Thursday by Jen is given by

Total part of distance covered in these four days by Jen is given by

Remaining part of distance will be covered on Friday to reach her goal which is given by

Hence, 5.875 miles run on Friday to reach her goal by Jen.