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iren2701 [21]
3 years ago
9

Solve for x: 6x + 1/4 (4x + 3) > 12 Ox> 10 7 Ox> 2 ox= 10 X = 2

Mathematics
1 answer:
daser333 [38]3 years ago
7 0

Given:

The inequality is:

6x+\dfrac{1}{4}(4x+3)>12

To find:

The values for x.

Solution:

We have,

6x+\dfrac{1}{4}(4x+3)>12

Using distributive property, we get

6x+\dfrac{1}{4}(4x)+\dfrac{1}{4}(3)>12

6x+x+\dfrac{3}{4}>12

7x>12-\dfrac{3}{4}

7x>\dfrac{48-3}{4}

On further simplification, we get

7x>\dfrac{45}{4}

Divide both sides by 7.

x>\dfrac{45}{7\times 4}

x>\dfrac{45}{28}

Therefore, the required solution is x>\dfrac{45}{28}.

Note: All options are incorrect.

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