Question

Solve for x: 6x + 1/4 (4x + 3) > 12 Ox> 10 7 Ox> 2 ox= 10 X = 2

Answer 1

Given:

The inequality is:

$6x+\dfrac{1}{4}(4x+3)>12$

To find:

The values for x.

Solution:

We have,

$6x+\dfrac{1}{4}(4x+3)>12$

Using distributive property, we get

$6x+\dfrac{1}{4}(4x)+\dfrac{1}{4}(3)>12$

$6x+x+\dfrac{3}{4}>12$

$7x>12-\dfrac{3}{4}$

$7x>\dfrac{48-3}{4}$

On further simplification, we get

$7x>\dfrac{45}{4}$

Divide both sides by 7.

$x>\dfrac{45}{7\times 4}$

$x>\dfrac{45}{28}$

Therefore, the required solution is $x>\dfrac{45}{28}$.

Note: All options are incorrect.