I need help please and thanks Number 9

PLEASE HELP!!! WILL MARK BRAINLIEST!! THX! A golfer hits a ball with an initial velocity of 32.7 m/s from the ground. Find the f

OLEGan [10]

Answer:

See below

Step-by-step explanation:

First Problem

The ball hits the ground when $h(t)=0$ , therefore:

$h(t)=-4.9t^2+v_0t+h_0$

$0=-4.9t^2+32.7t$

$0=t(-4.9t+32.7)$

$t=0$ and $t=\frac{32.7}{4.9}\approx6.67$

Since the ball is in the air before it hits the ground, $t=6.67$ (seconds) is the more appropriate choice.

Second Problem

The maximum height of the ball is determined when $t=-\frac{b}{2a}$ , therefore:

$t=-\frac{b}{2a}$

$t=-\frac{32.7}{2(-4.9)}$

$t=-\frac{32.7}{-9.8}$

$t\approx3.34$

This means that the height of the ball is at its maximum after 3.34 seconds:

$h(t)=-4.9t^2+32.7t$

$h(3.34)=-4.9(3.34)^2+32.7(3.34)$

$h(3.34)\approx54.55$

Thus, the answer is 54.55 (meters).

Third Problem

Refer to the second problem

Fourth Problem

$h(t)=-4.9t^2+32.7t$

$h(4.3)=-4.9(4.3)^2+32.7(4.3)$

$h(4.3)\approx50.01$

Therefore, the height of the ball after 4.3 seconds is 50.01 (meters).

Fifth Problem

The ball will be 24 meters off the ground when $h(t)=24$ , therefore:

$h(t)=-4.9t^2+32.7t$

$24=-4.9t^2+32.7t$

$0=-4.9t^2+32.7t-24$

$t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$t=\frac{-32.7\pm\sqrt{(32.7)^2-4(-4.9)(-24)}}{2(-4.9)}$

$t_1\approx0.84$

$t_2\approx5.83$

Therefore, the ball will be 24 meters off the ground after 0.84 (seconds) and 5.83 (seconds)

5 0

2 years ago

I cant get it right it says my answer is wrong

kow [346]

I’m learning this too.. so what you do it see what will the number he if it was a while line so to find that out you will add 7+7 and get 14 so that’s the whole
So 7 x 7 will equal 49 and 49 x 3.14 will give you 153.86 as the answer

5 0

3 years ago

18z + 9y - 4z + 15 - 8 + y - 2

Ahat [919]

Answer:

14z+10y+13 please mark brainliest if satisfied

Step-by-step explanation:

Simplify:

14z+10y+13

6 0

3 years ago

If the straight line passing through A(-7, -5) and B(-3, x) is parallel to another straight line of slope 2, find the value of x

Ostrovityanka [42]

X=3; you can set up a proportion using the slope equation. So (y[sub2]-y[sub1])/(x[sub2]-x[sub1])=2/1 then plug in the values and simplify. Then cross multiply and solve for x. Rest of work shown in the picture

8 0

3 years ago

Read 2 more answers

Suppose that a batch of 100 items contains 6 that are defective and 94 that are not defective. If X is the number of defective i

Taya2010 [7]

Answer: a) 0.5386 b) 0.0188

Step-by-step explanation:

Let X is the number of defective items in a randomly drawn sample of 10 items from the batch with parameter :

n= 10 and $p=\dfrac{6}{100}=0.06$

Binomial probability distribution:-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We have ,

a)

$P(X=0)=^{10}C_0(0.06)^0(0.94)^{10}\\\\=(1)(0.94)^{10}\\\\=0.538615114095\approx0.5386$

b)

$P(X>2)=1-P(x\leq2)=1-(P(x=0)+P(x=1)+P(x=2))\\\\=1-(^{10}C_0(0.06)^0(0.94)^{10}+^{10}C_1(0.06)^1(0.94)^{9}+^{10}C_2(0.06)^2(0.94)^{8})\\\\=1-(0.5386+(10)(0.06)(0.94)^9+(\dfrac{10!}{8!2!})(0.06)^2(0.94)^8)\\\\\approx1-(0.5386+0.3438+0.0988)\\\\=1-0.9812=0.0188$

Thus , $P(X>2)=0.0188$

4 0

3 years ago