Answer:
yes.
Step-by-step explanation:
sike.
Hello from MrBillDoesMath!
(x+2) ( x^2 + 3)
Discussion:
x^3 + 2x^2 + 3x + 6 =
( x^3 + 2x^2) + (3x + 6) = => factor "x^2" from the first term; factor 3
from the second term
x^2( x + 2) + 3( x+2) = => factor (x+2) from each term
Thank you,
MrB
