ln(20) + ln(5) = 2 ln(<em>x</em>)
ln(20×5) = ln(<em>x</em> ²)
ln(100) = ln(<em>x</em> ²)
100 = <em>x</em> ²
<em>x</em> = 10
Answer:
- f = -2/5a +14
- 12.4 ≈ 12 fish for 4 algae blooms
Step-by-step explanation:
The 2-point form of the equation for a line is useful when you are given two points to work with:
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
The independent variable (x) is apparently "algae blooms" and is to be represented by "a". The dependent variable (y) is "number of fish" and is to be represented by "f". So, we have ...
f = (4 -10)/(25 -10)(a -10) +10
f = -6/15(a -10) +10
f = -2/5a +14 . . . an equation for the scenario
Four a=4, the fish population is predicted to be ...
f = -2/5(4) +14 = 12.4
There will be about 12 fish when there are 4 algae blooms.
Answer:
Step-by-step explanation:
If x is the white dot on the graph:
From what it looks like, x is right between -35 and -34 x (which is -35.5).
If that is the case then none of the answers are correct since -35.5 is <u>equal or less</u> than x. (the sign looks like this: "
" )
But if you have to choose one of the answers then number 4 (-35.5 < x) would be closest.
Answer:
C
Step-by-step explanation:
sorry if I'm wrong-
