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Vikentia [17]
3 years ago
12

="TexFormula1" title="\frac{1}{\sqrt{7}-\sqrt{6} } +\sqrt{7} -\sqrt{6}" alt="\frac{1}{\sqrt{7}-\sqrt{6} } +\sqrt{7} -\sqrt{6}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Radda [10]3 years ago
5 0

Step-by-step explanation:

mark me brainlist.......

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If the point ( 4, -2 ) is reflected in the x-axis, then the new coordinate would be?
patriot [66]

Answer:

x will change y will not change... -4,-2

Step-by-step explanation:

if i am wrong then please inform me

7 0
3 years ago
What is x if 3x + 4 = 19?
Ymorist [56]
If you subtract 4 from both sides your left with 15, then divide by 3 to find x. your left with x=5
8 0
3 years ago
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Mcm de 12 21 63 <br> Encontrar el resultado
emmasim [6.3K]

Answer:

Lo mcm es 252.

Step-by-step explanation:

El objetivo de esta queston es encontrar el mínimo multiplo comun de estes tres numeros.

Para eso, factoramos estes numeros en valores primos, e despues multiplicamos estos factores.

12 21 63

12 - 21 - 63|2

6 - 21 - 63|2

3 - 21 - 63|3

1 - 7 - 21|3

1 - 7 - 7|7

1 - 1 - 1

2*2*3*3*7 = 252

Lo mcm es 252.

6 0
3 years ago
Geometry Question attached below
Soloha48 [4]

I'm sure there's an easier way to do this, but this method does work:

First, AB = CD = CG + GF + FD, so FG = 2.

By the Pythagorean theorem, in triangle AFD we get

1^2+3^2=A F^2\implies A F=\sqrt{10}

and in triangle BCG,

2^2+3^2=BG^2\implies BG=\sqrt{13}

Angles AFD and EFG form a vertical pair, so they are congruent and have measure

m\angle EFG=\tan^{-1}3

Similarly, angles BGC and FGE are congruent and have measure

m\angle FGE=\tan^{-1}\dfrac32

Then the remaining angle in triangle EFG has measure

m\angle FEG=\pi-\tan^{-1}3-\tan^{-1}\dfrac32

We can solve for the lengths of FE and GE exactly by applying the law of sines:

\dfrac{\sin\left(\pi-\tan^{-1}3-\tan^{-1}\frac 32\right)}2=\dfrac{\sin\left(\tan^{-1}3\right)}{GE}=\dfrac{\sin\left(\tan^{-1}\frac32\right)}{FE}

\implies GE=\dfrac{2\sqrt{13}}3,FE=\dfrac{2\sqrt{10}}3

Let s be the semiperimeter of triangle ABE, so that

s=\dfrac{AB+BE+EA}2

Then according to Heron's formula, the area of triangle ABE is

\sqrt{s(s-AB)(s-BE)(s-EA)}=\dfrac{25}2

5 0
4 years ago
Please help me please
charle [14.2K]
Its A or C Because you cannot have 6/5
7 0
3 years ago
Read 2 more answers
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