Y=1/x is a reciprocal function & its shape is a special hyperbola with one branch located in the 1st Quadrant and the second in the 3dr Quadrant and both are symmetric about the origin O.
If a> 1 → y=a/x and the 2 branches are equally stretched upward & downward
about the center O.
If 0 < a < 1→y =a/x, the 2 branches are equally stretched downward and upward about the center O.
If a<0, then the 2 legs are in the 2nd and 4th Quadrant respectively
Numbers I think I'm not that smart
.5 as a decimal and 50% as a percent
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
