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3 years ago

Please I don’t undersatnd what I have to do for the second question. This is a GCF (greatest common factor) problem.

Mathematics

1 answer:

andreev551 [17]3 years ago

8 0

Answer: You need to find the multiples of each of the numbers and choose the largest one that each number has

Step-by-step explanation:

42 write what can be multiplied to get 42

1 and 42 , 2 and 21, 3 and 14, 6 and 7

70 write what can be multiplied to get 70

1 and 70, 2 and 35, 5 and 14, 7 and 10

56- write what can be multiplied to get 56

1 and 56, 2 and 28, 4 and 14, 7 and 8

Now look back and see what numbers they all have in common, which is 2 and 14 in this case

You pick the bigger number because it is a GCF problem, which is 14, and that is the number of rows

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SOMEONE HELP !!!!! PLEASEEEEEEEEEE!!!¡¡¡!¡!¡

vladimir1956 [14]

Answer is a, 57.49.

17.42-12.60-9.62= $-4.80+62.29=57.49

4 0

3 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago

What the rate of change for f(t)=70(5/2)^t help

denis23 [38]

5/2
70 is the constant number that doesn’t change, but anytime you increase t you are raising it above 5/2. So every time you grow 5/2.

3 0

2 years ago

Select the best equation needed to solve for x; then solve for x:

Natali [406]

Step-by-step explanation:

A. 5x=12x-14

you will simplify the equation to the form, which is simple to understand

5x=12x-14

We move all terms containing x to the left and all other terms to the right.

+5x-12x=-14

We simplify left and right side of the equation.

-7x=-14

We divide both sides of the equation by -7 to get x.

x=2

B. 5B+12=BB=28

you will move all terms to the left:

.5B+12-(BB)=0

you will move all terms containing B to the left, all other terms to the right

.5B-BB=-12

7 0

3 years ago

Read 2 more answers

Vlad spent 20 minutes on his history homework and then completely solved x math problems that each took 2 minutes to complete wh

frozen [14]

Answer:

y = 2x + 20

$y\geq 20$

$x\geq 0$

Step-by-step explanation:

Vlad spent 20 minutes on history. Then Vlad spent 2 minutes on each math problem for homework, this is 2x. So in total, he spent 20+2x on homework. Depending on how many problems he did, the total time y can be found. This is the equation 20+2x=y.

If Vlad did 0 math problems then he spent at least 20 minutes on homework from history. This is the constraint $y\geq 20$ .

We also know Vlad can do many math problems but the least amount he did was 0, so the second constraint is $x\geq 0$ .

5 0

3 years ago