1 1/3 hours. 3/4 plus 7/12 equals 1 1/3. Hope this helps
kitten : puppies
3:1
<em>Total</em><em> </em><em>no</em><em>.</em><em> </em>
3+1 = 4
<em>Ther</em><em>efore</em>
24÷4 = 6
(each of ratio represent 6 animals)
<em>So</em><em>,</em>
3×6
= 18
Answers
18 kitten
Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
= 
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
Tn = a + (n-1)d
when n = 12, tn = 63
63 = a + (12-1)*5
a = 63 - 55 =8
tn or an
= 8 + (n-1) 5
= 3 + 5n
Hope this helps
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.