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Alexxandr [17]
3 years ago
8

Marta has a bracelet made up of 3 red, 5 yellow, and 24 green beads.What is the ratio of yellow beads to beads that are not yell

ow
Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

.....................

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Which is an equation in point slope form of the line that passes through the points (7, 5) and (-4, -1)
emmasim [6.3K]

Answer:

y = (6/11)x + 13/11

Step-by-step explanation:

y = mx + c

m = (-1-5)/(-4-7) = -6/-11 = 6/11

y = (6/11)x + c

When x = 7, y = 5

5 = (6/11)(7) + c

5 = 42/11 + c

c = 5 - 42/11

c = 13/11

y = (6/11)x + 13/11

11y = 6x + 13

5 0
3 years ago
If 8y-8=24 find the value of 2y
Aloiza [94]

Answer:

8

Step-by-step explanation:

8y-8=24

+8 +8

8y=32

32/8 = 4

y=4

4*2=8

4 0
3 years ago
Read 2 more answers
What is the diameter of a hemisphere with a volume of 8514 cm', to the nearest
Mandarinka [93]

Answer:

32.0 cm

Step-by-step explanation:

volume of a hemisphere = (2/3)πr3

r = cube root (Volume * 3/2 * 1/π )

r = cube root ( 8514 * 3/2 * 1/π)

r = 15.96

in the nearest tenth r = 16.0 cm

D= 2r

D= 2(16)

D= 32cm

6 0
2 years ago
Read 2 more answers
Find X and Y and show please show calculations
torisob [31]

Answer:

Y = 90

X = 52

Step-by-step explanation:

Y is on a straight line. The sum of the angles on a straight line is 180.

The only other angle (that is marked) on this straight line, is a 90 degree one. So, <y + 90 = 180.

<y = 90.

Now <x + 38 = 90

so, x = 52

6 0
3 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
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