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eduard
3 years ago
7

Freddy owns a lot measuring 80 ft. x 120 ft. The city puts in a new street on the front and the side of his house and assesses h

im 6 cents per square foot based on the area of this lot. His costs are ______.
Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

His costs are $ 596

Step-by-step explanation:

Given,

The measurements of the lot = 80 ft. x 120 ft,

So, the area of the lot = 80 x 120

                                     = 9600 ft².

Since, the charges per square feet = 6 cents

Thus,

The total charges for the lot

= area in square ft × cost per square ft

= 9600 × 6      

= 59600 cents  

= 596 dollars    ( ∵ 100 cents = 1 dollar )

Hence, his costs are <u>$ 596</u>

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2774989

________________


Find the multiplicative inverse of

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The inverse multiplicative of  \mathsf{z=a+bi}  is

\mathsf{\dfrac{1}{z}}\\\\\\&#10;=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\&#10;=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\&#10;=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}

=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\&#10;=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\&#10;\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}

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For this question,

\mathsf{z=6+2i}


So,

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\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

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