1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fiasKO [112]
3 years ago
13

Write a function named “createPurchaseOrder” that accepts the quantity (integer), the cost per item(double), and the description

(string). It will return a newly created PurchaseOrderobject holding that information if they are valid: quantity and cost per item cannot be negative and the description can not be empty or blank(s). When it is invalid, it will return NULL to indicate that it cannot create such PurchaseOrderobject.
Computers and Technology
1 answer:
Leona [35]3 years ago
4 0
#include
Program: using namespace std;
string createPurchaseOrder0;
int main(
{
cout<return 0;
}
string createPurchaseOrder(
{
int qty;
double costPerltem;
string description,info="":
cout<<"Enter Quantity:
cin>>qty;
cout<<"Enter cost per item: "
cin>>costPerltem;
cout<<"Enter Description: "
cin>>description;
if(qty<0 I| costPerltem<0
Idescription.compare(''"')==0)
cout<<'InThe entered data is invalid!":
info="":
else
"
cout<<"'InThe entered data is valid!":
info=info+"'(nQuantity: "+to_string (qty) +" In";
info=info+"Cost per item:
"†to_string (costPerltem)+"In";
info=info+"Description: "description+" In";
return info;

Output:
You might be interested in
A posting error is:
Sunny_sXe [5.5K]

Answer:

The correct answer to the given question is option D) Any or all of the above.

Explanation:

A posting error is a type of error which is related to ledger and would include the errors like -

Posting wrong amount on the right side of account

Posting right amount on the wrong side of right account

Posting an amount twice and posting omission

Posting wrong amount to wrong side of right account

Posting correct amount on wrong account on right side

So by knowing all the given above points, it is quite clear that the correct option is D.

7 0
3 years ago
Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen
Verdich [7]

Answer:

Replace <STUDENT CODE> with

for (i = 0; i < SCORES_SIZE; ++i) {

       if(lowerScores.at(i)<=0){

           lowerScores.at(i) = 0;

       }

       else{

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Explanation:

To do this, we simply iterate through the vector.

For each item in the vector, we run a check if it is less than 1 (i.e. 0 or negative).

If yes, the vector item is set to 0

If otherwise, 1 is subtracted from that vector item

This line iterates through the vector

for (i = 0; i < SCORES_SIZE; ++i) {

This checks if vector item is less than 1

       if(lowerScores.at(i)<1){

If yes, the vector item is set to 0

           lowerScores.at(i) = 0;

       }

       else{

If otherwise, 1 is subtracted from the vector item

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Also, include the following at the beginning of the program:

<em>#include <vector></em>

8 0
3 years ago
Help pls put them in order for me??
Natalija [7]

Answer: i can't see the hole thing?

Explanation:

3 0
3 years ago
Read 2 more answers
PLS HELP I GOT 30 MINS TO TURN THIS IN!!!
tekilochka [14]

Answer:

it is actually a phone video gaming tv and stuff that you play with like cars and other stuff

Explanation:

4 0
3 years ago
Read 2 more answers
Write the program to solve quadratic equations, but if the discriminant is negative, output
Firdavs [7]

Answer:

PROGRAM  QuadraticEquation Solver

  IMPLICIT  NONE

REAL :: a, b, c ;

  REA :: d ;

  REAL  :: root1, root2 ;

//read in the coefficients a, b and c

  READ(*,*)    a, b, c  

  WRITE(*,*)   'a = ', a

  WRITE(*,*)   'b = ', b

  WRITE(*,*)    'c = ', c

  WRITE(*,*)

// computing the square root of discriminant d

  d = b*b - 4.0*a*c

  IF (d >= 0.0) THEN              //checking if it is solvable?

     d     = SQRT(d)

     root1 = (-b + d)/(2.0*a)     // first root

     root2 = (-b - d)/(2.0*a)     // second root

     WRITE(*,*)  'Roots are ', root1, ' and ', root2

  ELSE                            //complex roots

     WRITE(*,*)  'There is no real roots!'

     WRITE(*,*)  'Discriminant = ', d

  END IF

END PROGRAM  QuadraticEquationSolver

8 0
4 years ago
Other questions:
  • The ______ identifies the path for the currently open folder
    8·2 answers
  • A(n) ____________________ defines the number and type of daemons that are loaded into memory and executed by the kernel on a par
    12·1 answer
  • How could the provisions in the new health reform bill improve access to care?
    14·1 answer
  • What is used for World Wide Web?
    7·1 answer
  • You should use html elements instead of server controls when
    11·1 answer
  • What is the recommended solution to configure this automated behavior? UC has a requirement that an opportunity should have a fi
    8·1 answer
  • Peter has recently bought a media player and a digital camera he wants to buy a memory card and then use devices which memory do
    11·2 answers
  • Which of the following statements represents the number of columns in a regular two-dimensional array named values?
    9·1 answer
  • Which rotation speed is not a typical spindle rotation speed for magnetic hard drives?3100; 5400; 7200; 10000
    8·1 answer
  • The space where text and content is entered and positioned for onscreen reading or printing
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!