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3 years ago

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Physics

2 answers:

vivado [14]3 years ago

8 0

Answer:

what is your question?..... .

IgorC [24]3 years ago

6 0

Answer:

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A rubber rod rubbed with fur acquires a charge of -4,8×10(-9)C. What is the charge on the fur? How much mass is transferred to r

mote1985 [20]

1) The charge left on the fur is equal and opposite to the charge transferred to the rod:
$Q=+4.8 \cdot 10^{9} C$
In fact, when the rod is rubbed with the fur, a net charge of $Q=-4.8 \cdot 10^{-9} C$ has been transferred to the rod, leaving it negatively charged. If we assume the fur was initially neutral, this means that we have now an excess of positive charges on the fur, and the amount of this charge must be equal (in magnitude, but with opposite sign) to the charge transferred to the rod.

2) The mass transferred to the rod is equal to the total mass of the electrons transferred to the rod.
The charge transferred to the rod is
$Q=-4.8 \cdot 10^{-9} C$
The charge of 1 electron is
$e=-1.6 \cdot 10^{-19} C$
So the number of electrons transferred is
$N= \frac{Q}{e}= \frac{-4.8 \cdot 10^{-9} C}{-1.6 \cdot 10^{-19} C}=3.0 \cdot 10^{10}$

The mass of 1 electron is $m=9.1 \cdot 10^{-31} kg$ , therefore the total mass transferred to the rod is
$M=Nm=(3 \cdot 10^{10})(9.1 \cdot 10^{-31} kg)=2.73 \cdot 10^{-20} kg$

7 0

3 years ago

The magnitude of the gravitational force between two objects is 20. Newtons. If the mass of

sergeinik [125]

Answer: 80N

Explanation:

5 0

3 years ago

An infinite long straight wire is uniformly charged, the charge density is a. Use Coulomb's law to calculate the electric field

bixtya [17]

Answer:

$\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R$

Explanation:

Since the wire is infinitely long, we will use Gauss' Law:

$\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}$

We will draw an imaginary cylindrical surface with height h around the wire. The electric flux through the imaginary surface will be equal to the net charge inside the surface.

In that case, the net charge inside the imaginary surface will be the portion of wire with height h. Then the charge of that portion will be equal to

$Q_{enc} = ah$

The left-hand side of the Gauss' Law is the flux through the imaginary surface. Since we choose our surface as a cylinder, of which we know the area, we do not have to take the surface integral.

$\int\vec{E}d\vec{a} = E2\pi R h$

where R is the radius of the imaginary cylinder.

Finally, Gauss' Law gives

$E2\pi Rh = \frac{ah}{\epsilon_0}\\E = \frac{a}{2\pi \epsilon_0 R}$

The vector expression is

$\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R$

As you can see, the electric field is independent from the height h, since that is merely an imaginary cylinder to apply Gauss' Law. In the end, what matters is the charge density of the wire and the distance from the wire.

4 0

4 years ago

By now, you know that sound is produced by vibrations. These vibrations can travel through solids, liquids, and gases, but not t

mamaluj [8]

I think d because it's too far to reach.

3 0

4 years ago

Read 2 more answers

Which type of wave is a sound wave ?

mestny [16]

Technically, both B and D are correct when transmitted through solids, but your answer (and the answer I got from taking the test) will be

D) Longitudinal

Hope this helps!

4 0

3 years ago

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Ganda wow innova jhbjguyhyujj