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Yuliya22 [10]
3 years ago
13

What two principal factors affect the force of air resistance on a falling object?

Physics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:i dont know

Explanation:i dont know

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A ball is projected horizontally from the top of a cliff. At the same moment, a second identical ball is dropped from rest from
almond37 [142]

Answer:3

Explanation:

First ball is thrown with horizontal velocity while other ball is dropped from cliff such that both have zero vertical velocity. So both balls have to cover a distance equal to the height of cliff with same initial velocity.

time taken is given by t=\sqrt{\frac{2h}{g}}

where h=height of cliff

g=acceleration due to gravity

horizontal velocity to first ball will make the ball to travel more horizontal distance as compared to second ball.

Option 3 is correct

4 0
3 years ago
2. If Peter is traveling .25 m/s on his bike, how long will it take him to reach
Semmy [17]

Answer:

48 seconds

Explanation:

Since S=d/t, plug in the known values and solve

0.25m/s=12m/t

0.25m/s*t=12m

t=12m/0.25m/s

t=48 seconds

7 0
3 years ago
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If a vector 2ỉ +3j +8k is perpendicular to the<br> vector 4j-4i + ak, then the value of a is
natita [175]

Explanation:

if two vectors are perpendicular to each other then thier dot product is equal to zero so (2i+3j+8k).(-4i+4j+ak)=0 (2)(-4) +(3)(4)+(8)(a) =0 -8+12+8a=0 4+8a=0 8a=-4

a =  \frac{ - 4}{8}

a =  \frac{ - 1}{2}

4 0
3 years ago
Why is physics the hardest subject
horrorfan [7]
Physics can demand that you start with a specific result and make general rules. Not reading the text and not solving exercises makes understanding almost impossible. It also involves a lot of math which most people do not like.
3 0
2 years ago
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An object's distance from a converging lens is 3.78 times the focal length. a) Determine the location of the image. Express the
Romashka-Z-Leto [24]

Answer:

a) v=1.36f

b)m=.36

c) real

d) Inverted

Explanation:

a)

In this question we have given,

object distance from converging lens,u=-3.78f

focal length of converging lens,=f

we have to find location of image,v=?

and magnification,m=?

we know that u, v and f are related by following formula

\frac{1}{f} =\frac{1}{v}- \frac{1}{u}.............(1)

put values of f u in equation (1)

we got,

\frac{1}{f} =\frac{1}{v}- \frac{1}{-3.78f}

\frac{1}{f}-\frac{1}{3.78f} =\frac{1}{v}

\frac{2.78}{3.78f} =\frac{1}{v}

or

v=1.36f

b) Magnification, m=\frac{v}{u} \\m=\frac{1.36f}{3.78f}\\m=.36

c)

Here the object is located further away from the lens than the focal point therefore image is real image and inverted.

d) image is inverted

7 0
3 years ago
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