3 years ago

Prove the following question

Mathematics

1 answer:

TEA [102]3 years ago

3 0

Answer:

1=1

Step-by-step explanation:

x = theta

[cos(x) * 1/sin(x) * sin(x)/cos(x)] / [sin(x) * 1/cos(x) * cos(x)/sin(x)] = [cos(x)/cos(x) * sin(x)/sin(x)] / [sin(x)/sin(x) * cos(x)/cos(x)] = [1*1]/[1*1] = 1

Because csec(x) = 1/sin(x) , sec(x) = 1/cos(x), tan(x) = sin(x)/cos(x) & cot(x) = cos(x)/sin(x)

You might be interested in

Which choice is equivalent to the fraction below when x is an appropriate value? Hint: Rationalize the denominator and simplify.

densk [106]

$\frac{3}{3- \sqrt{6x} } = \frac{3}{3- \sqrt{6x} } \times \frac{3+ \sqrt{6x} }{3+ \sqrt{6x} } \\ = \frac{3(3+ \sqrt{6x})}{3^2-( \sqrt{6x} )^2} = \frac{3(3+ \sqrt{6x})}{9-6x} \\ =\frac{3(3+ \sqrt{6x})}{3(3-2x)}=\frac{3+ \sqrt{6x}}{3-2x}$