Answer:
53x - 4 = 30
53x = 30 +4
53x = 34
x= 34/53
I don't see a answer that matches the answer to the problem that you stated. Check problem.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The x intercepts are 0 and
1000 - 2x = 0 given condition
1000 = 2x Divide by 2
500 = x
So the two intercepts are 0,0 and 500,0
The intercepts mean that for (0,0) the phone company hasn't charged anything, yet. For 500,0 the phone company can sell a single phone -- not when they cost 500 dollars apiece.
The answer to the B part is completing the square.
r(x) = - 2x^2 + 1000x
r(x) = -2(x^2 - 500x )
1/2 ( 500) = 250
250^2 is what you put inside the bracket's to complete the square.
r(x) = - 2(x^2 - 500x + 250^2) + 2*250^2
r(x) = -2(x - 250)^2 + 2*62500
r(x) = - 2(x - 250)^2 + 125000
They should sell their phones at 250 dollars a piece. The total revenue is 125000. Your graph shows exactly the same thing.
Answer:
Length = 17 feet, Width = 5 feet
Step-by-step explanation:
Given:
The area of a rectangular wall of a barn is 85 square feet.
Its length is 12 feet longer than the width.
Question asked:
Find the length and width of the wall of the barn.
Solution:
Let width of a rectangular wall of a barn = 
<u>As length is 12 feet longer than the width.</u>
Length of a rectangular wall of a barn = 
As we know:


Subtracting both sides by 85

As width can never be in negative, hence width of a rectangular wall of a barn =
= 5 feet
Length of a rectangular wall of a barn = 
Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.
The answer would be “-876”
There are a couple ways to do this, but basically you need to convert the units.
<span>7 yards x 3 ft/yard = 21 feet </span>
<span>4 yards x 3 ft/yard = 12 feet </span>
<span>So the area (in sq. ft) will be: </span>
<span>21 x 12 </span>
<span>= 252 sq. ft. </span>
<span>Alternatively, you can figure the area in square *yards* and then multiply by 9 sq. ft per sq. yard. </span>
<span>7 yards x 4 yards x 9 sq. ft/sq. yard </span>
<span>= 252 sq. ft.
hope this helps :)</span>