Solve algebraically for all values of x: 8x^4-70x^3-18x^2
1 answer:
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Answer:
The given equation is never possible i.e cos ( A - B ) ≠ cos A - cos B
Step-by-step explanation:
Given as :
Is cos ( A - B ) = cos A - cos B
To check this possibility , Let us put the value of angle A and B on both side of equation
Now, Let A = 60° and B = 30°
<u>From Left hand side equation </u>
cos ( A - B ) = cos ( 60° - 30° )
Or, cos ( A - B ) = cos 30°
∴ cos ( A - B ) =
or, cos ( A - B ) = 0.866
<u>From Right hand side equation</u>
cos A - cos B = cos 60° - cos 30°
Or, cos A - cos B = -
∴, cos A - cos B = 0.5 - 0.866
I.e cos A - cos B = - 0.366
So, Left hand side ≠ Right hand side
<u>Since while equating the values of angle A and b in the given equation on both sides, we get that the value of both sides are not equal , Thus we can say that the given equation is not equal to each other .</u>
Hence given equation is never possible i.e cos ( A - B ) ≠ cos A - cos B Answer