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Afina-wow [57]
3 years ago
12

Please answer/do 3-7!! Whoever does it right, i will give brainlest! :) also, PLEASE FILL IT OUT EITHER ON PAPER/ PHONE etc. !!!

Mathematics
2 answers:
meriva3 years ago
7 0

Answer:

3-7 is negitive 4 in your answer it's 3-7 = -4

Step-by-step explanation:

It's negitive four because if you subtract you will get 4 but since it's other way around. And if you do It, it will say that even if there is no negitive sign it won't change the problem because it's still the same problem.

1) 3 - 7

2) there are 3 ways to do this to get the answer:

1) 3/7

2) 7 + 3 - 4 + 3

3) now 7 + 3 is ten - 7 is 3 + 4 is 7, so then if you do 3 - 7 you get negitive four

4) now check your answer by subtracting 3 and 7

5) then you get -4

btw: ( hope this helped :) )

Klio2033 [76]3 years ago
6 0
3. 54.87 + 7.48 = 62.35 55 + 7 = 62

5. 0.215 + 3.74 = 3.955 0 + 3 = 3

7. 18.419 - 6.47 = 11.949 I’m assuming it should be 18 - 6 = 11 because of the decimal but I could be wrong about it
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ruslelena [56]

Answer:

A. The interval will be narrower if 15 men are used in the sample.

Step-by-step explanation:

Hello!

When all other things remain the same, which of the following statements about the width of the interval is correct?

A. The interval will be narrower if 15 men are used in the sample.

B. The interval will be wider if 15 men are used in the sample.

C. The interval will be narrower if 5 men are used in the sample.

D. The interval will be narrower if the level is increased to 99% confidence.

E. The interval will be wider if the level is decreased to 90% confidence.

Consider that the variable of interest "Xd: Difference between the peak power of a cyclist before training and after training" has a normal distribution. To construct the confidence interval for the population mean of the difference you have to use a pooled t-test.

The general structure for the CI is "point estimate"±" margin fo error"

Any modification to the sample size, sample variance and/or the confidence level affect the length of the interval (amplitude) and the margin of error (semiamplitude)

The margin of error of the interval is:

d= t_{n-1;1-\alpha /2} * (Sd/n)

1) The sample size changes, all other terms of the interval stay the same.

As you can see the margin of error and the sample size (n) have an indirect relationship. This means, that when the sample size increases, the semiamplitude decreases, and when the sample size decreases, the semiamplitude increases.

↓d= t_{n-1;1-\alpha /2} * (Sd/↑n)

↑d= t_{n-1;1-\alpha /2} * (Sd/↓n)

Correct option: A. The interval will be narrower if 15 men are used in the sample.

2) The confidence level has a direct relationship with the semiamplitude of the interval, this means that when the confidence level increases, so do the semiamplitude, and if the level decreases, so do the semiamplitude:

↓d= ↓t_{n-1;1-\alpha /2} * (Sd/n)

↑d= ↑t_{n-1;1-\alpha /2} * (Sd/n)

I hope it helps!

4 0
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Answer:

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Step-by-step explanation:

simplify both ratios

6/9 divide by 3 to =2/3

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Pachacha [2.7K]

Answer: 8/9

Step-by-step explanation:

8/9 cannot be simplified. It's already in simplest form. if you want to turn it into decimal the answer will be .8 (bar notation above 8)

8 0
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lilavasa [31]

Answer:

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Step-by-step explanation:

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