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Elza [17]
3 years ago
11

A number z is fewer than 3/4​

Mathematics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

z < ¾

Step-by-step explanation:

Or z < 0.75

...........

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Is (2, 6) a solution to this system of equations?<br> y = -x + 8<br> y = 5x - 4<br> yes<br> no
Alexxx [7]

Answer:

Yes

Step-by-step explanation:

To see is (2, 6) is a system, we can plug it into the system to check if it gives us true statements:

6 = -2+8

6 = 6

6 = 5(2)-4

6 = 10-4

6 = 6

Both of the equations are true, therefore (2, 6) is a solution to this system.

6 0
2 years ago
What is the value of x to the nearest tenth.<br><br><img src="https://tex.z-dn.net/?f=%20%5Ctan%2834%20%29%20%3D%20%20%5Cfrac%7B
Rina8888 [55]

tan(34)=\frac{x}{20} \\\frac{tan(34)}{1} * \frac{x}{20}\\x= 20*tan(34)

*use calculator to get final product

x = 13.490

*x is not equal to 13.490 it is an estimation so use (≈)

8 0
3 years ago
URGENT!!!!
babunello [35]

The equation of the hyperbola in standard form is \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

Step-by-step explanation:

Let us revise the equation of the hyperbola

The standard form of the equation of a hyperbola with  center (h , k) and transverse axis parallel to the y-axis is  \frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1

  • The length of the transverse axis is 2a  
  • The length of the conjugate axis is 2b  

∵ The center of the hyperbola is (1 , 4)

∴ h = 1 and k = 4

∵ The transverse axis is parallel to the y-axis

∴ The form of the equation is  \frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1

∴ The length of the transverse axis is 2a  

∵ The length of the transverse axis is 20 units

- Equate 2a by 20 to find a

∴ 2a = 20

- Divide both sides by 2

∴ a = 10

∵ The length of the conjugate axis is 2b

∵ The length of the conjugate axis is 16

- Equate 2b by 16 to find b

∴ 2b = 16

- Divide both sides by 2

∴ b = 8

- Substitute the values of h, k, a, and b in the form of the equation

∴  \frac{(y-4)^{2}}{(10)^{2}}-\frac{(x-1)^{2}}{(8)^{2}}=1

∴  \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

The equation of the hyperbola in standard form is \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

Learn more:

You can learn more about the hyperbola in brainly.com/question/4054269

#LearnwithBrainly

4 0
3 years ago
5d2-50d+125 = <br> Fully factor each expression
Ede4ka [16]
First, let's start off by simplifying as much as possible before factoring.

5d^2 - 50d + 125

We can divide all the numbers by 5 in order to simplify it:

5(d^2 - 10d + 25)

Now all we need to do is factor.
Since -5*-5 = 25 and -5 - 5 = -10, we can use this to factor:

5(d - 5)(d - 5)
Or
5(d - 5)^2
8 0
3 years ago
If Sophie gets $26.00 and Jack gets four times the amount as Sophie. How much do Jack get?​
alina1380 [7]

Answer:

he gets 104$

Step-by-step explanation:

104 dollars

26x4=104

5 0
3 years ago
Read 2 more answers
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