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Tatiana [17]
2 years ago
15

Il record del mondo sulla maratona appartiene al grande Eliud Kipchoge con il tempo di 2h 01' 39"

Physics
1 answer:
SVETLANKA909090 [29]2 years ago
3 0

Answer: 7260,39

Explanation:

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Ursula is a student of Kantian philosophy who argues that we should never use people as a means to an end unless
ANTONII [103]

Answer: we embrace and are simultaneously respecting their rational autonomy

Explanation:

Ursula is a student of Kantian philosophy who argues that we should never use people as a means to an end unless we embrace and are simultaneously respecting their rational autonomy

8 0
4 years ago
The gauge pressure for the air in a balloon equals 1.01 x 10^5 Pa. If atmospheric pressure is equal to 1.01 x 10^5 Pa, what is t
Kobotan [32]
Absolute Pressure = Atmospheric Pressure + Gage Pressure

Absolute Pressure = 1.01 x 10^5 Pa + 1.01 x 10^5 Pa = D. <span>2.02 x 10^5 Pa</span>
4 0
3 years ago
Read 2 more answers
You illuminate a slit with a width of 70.3 μm with a light of wavelength 719 nm and observe the resulting diffraction pattern on
Zielflug [23.3K]

Answer:

4.3 cm

Explanation:

We are given that

Width,d=70.3\mu m=70.3\times10^{-6} m

1\mu m=10^{-6} m

Wavelength,\lambda=719 nm=719\times 10^{-9} m

1nm=10^{-9} m

r=2.11 m

We have to find the width in cm of the pattern.

The angle for the first minimum m=1

sin\theta_{min}\approx \theta=\frac{\lambda}{d}=\frac{719\times 10^{-9}}{70.3\times 10^{-6}}=0.0102 rad

y=r\theta=2.11\times 0.0102=0.0215 m

The width of the pattern=2y=2\times 0.0215=0.043 m=0.043\times 100=4.3 cm

8 0
3 years ago
In a physics lab, a 60-kg student runs up a 2.0-meter tall flight of stairs in 1.5 seconds. The work done to get to the top is 1
tester [92]
<span>The student's power rating is approximately 800W.
</span>
Power is the rate of doing work. Its SI unit is Watt. 1 W = 1J/sec

Given: <span>The work done to get to the top is 1200 Joules
</span>
Time = 1.5 seconds.

Power = \frac{work done}{time} &#10;=  \frac{1200J}{1.5 sec} &#10;= 800J/sec &#10;= 800W
3 0
4 years ago
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
Triss [41]

Answer:

2.1406 ×10^6 m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

now mass of electron =9.11×10^{-31}

so for electron

\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec

so the velocity of electron will be 2.1406×10^6 m/sec

4 0
3 years ago
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