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3 years ago

Which statement is true about the atoms in helium gas?

Physics

2 answers:

Andre45 [30]3 years ago

8 0

B.
<span>They are not closely packed. </span>

Alex Ar [27]3 years ago

5 0

The answer is B :) I hope this helps

You might be interested in

At what rate is 444kg object accelerating if a force of 7,700N is applied to it?

vlabodo [156]

Answer:

646,800

Explanation:

If you multiply the 7,700N and the 444kg your answer would be 646,800.

7 0

4 years ago

In which two locations do tropical cyclones occur?

igor_vitrenko [27]

<span>northwest Australia between Exmouth and Broome in Western Australia and in northeast Queensland between Port Douglas and Maryborough</span>

3 0

4 years ago

Read 2 more answers

In an oscillating LC circuit, L = 4.24 mH and C = 3.02 μF. At t = 0 the charge on the capacitor is zero and the current is 2.38

Ann [662]

Answer:

a) 2.693*10^-4 C

b) 8.875*10^-5 s

c) 2.96 W

Explanation:

Given that

Inductance of the circuit, L = 4.24 mH

Capacitance of the circuit, C = 3.02 μF

Current in the circuit, I = 2.38 A

See attachment for calculations

7 0

3 years ago

Read 2 more answers

A 70.0 kg ice hockey goalie, originally at rest, has a 0.110 kg hockey puck slapped at him at a velocity of 31.5 m/s. Suppose th

NISA [10]

Answer

given,

mass of the goalie(m₁) = 70 kg

mass of the puck (m₂)= 0.11 kg

velocity of the puck = 31.5 m/s

elastic collision

$v_1=\dfrac{m_2-m_1}{m_1+m_2}v_1+\dfrac{2m_2}{m_1+m_2}v_2$

$v_{pf}=\dfrac{0.11-70}{0.11+70}31.5+\dfrac{2m_2}{m_1+m_2}\times (0)$

$v_{pf}=-31.4\ m/s$

$v'_2 = \dfrac{2m_1v_1}{m_1+m_2}-\dfrac{(m_2-m_1)v_2}{m_2+m_1}$

$v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}-\dfrac{(0.11-70)\times 0}{m_1+m_2}$

$v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}$

$v_{gf} = 0.0988\ m/s$

4 0

3 years ago

A point charge q is at the point x = 0, y = 0, z = 0. An imaginary hemispherical surface is made by starting with a spherical su

VladimirAG [237]

Answer:

$282.5 N.m^2/C$

Explanation:

Use the Coulomb's law. According to it, the flux through entire sphere would be

$\phi = \frac{q}{\epsilon_o}$

where, q is the total charge enclosed in the sphere and $\epsilon_o$ is the absolute permittivity.

Thus, the flux through the hemisphere would be half of it i.e.

$\phi = \frac{q}{2\epsilon_o}\\\phi =\frac{5\times 01^{-9}}{2\times 8.85\times10^{-12}}\\\phi =282.5 N.m^2/C$

6 0

4 years ago