PLEASE HELP
1 answer:
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The value of 
, 
, and 
for each schools is given in the first picture below.
is the lower quartile
is the median
is the upper quartile
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
Answer:
The painting is 42.13 feet above the platform
Step-by-step explanation:
Refer the attached figure .
A particular painting forming an angle of 50 degrees with a camera platform .
∠ABC = 50°
We are also given that the light is 55 feet from the wall where the painting hangs
i.e. AB = 55 feet.
Now we are required to find how high above the platform is the painting. i.e. AC
So, we will use trigonometric ratio :
Thus the painting is 42.13 feet above the platform
